The atom that is most likely to lose an electron is lithium (Li).
<h3>What is electronegativity?</h3>
Electronegativity is the tendency, or a measure of the ability, of an atom or molecule to attract electrons when forming bonds.
On the other hand, electropositivity is the tendency of an atom to release electrons to form a chemical bond.
Chemical elements that lose electrons become positively charged while elements that gain electrons become negatively charged.
Metals are most likely to lose electrons to form positive ions. Examples of metals are lithium in group 1, calcium in group 2, aluminium in group 3 etc.
Learn more about electropositivity at: brainly.com/question/17762711
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The data gotten from ice cores could scientists tell the about future climate change.
Yes...
Explanation:
Ionisation energy is the amount of energy, which is required to remove the most loosely bound electron(s) from an isolated gaseous atom to form a positive ion.
In forming an ionic bond, one atom must form a cation by losing one or more electrons. In general, elements having low ionisation energies have a more favourable chance to form a cation, thereby having a greater tendency to form ionic bonds.
Thus, lower ionization energy of metallic elements favours the formation of an ionic bond. It is because of low ionization energy that the alkali and alkaline earth metals, form ionic compounds.
Answer:
0.5 × 10²³ atoms of iodine
Explanation:
Given data:
Mass of calcium iodide = 12.75 g
Number of atoms of iodine = ?
Solution:
First of all we will calculate the number of moles of calcium iodide.
Number of moles = mass/ molar mass
Number of moles = 12.75 g/ 293.9 g/mol
Number of moles = 0.04 mol
In one mole of calcium iodide there are two moles of iodine.
Thus in 0.04 moles:
0.04 mol × 2 = 0.08 moles of iodine
Now we will use the Avogadro number:
The given problem will solve by using Avogadro number.
It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.
The number 6.022 × 10²³ is called Avogadro number.
1 mole = 6.022 × 10²³ atoms
0.08 moles of iodine × 6.022 × 10²³ atoms / 1 mol
0.5 × 10²³ atoms of iodine.