A 2.200-g sample of quinone (C6H4O2) is burned in a bomb calorimeter whose total heat capacity is 7.854<span> kJ/°C. The temperature of the calorimeter increases from 23.44 to </span>30.57 °C<span>. </span>
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Assuming that the force of friction does not equal to the force at which you are pulling at, hence Fnet is not zero, to solve for acceleration need to use the following equation:
Fnet = ma
a = Fnet/m
a = 50 N/10 kg
a = 5 N/kg or a = 5 m/s^2.
Answer:
it'a answer number 2
Explanation: you divide the mass by volume and 32.2 divided by 4 is 8.05
Moles of Carbondioxide-CO₂ produced = 20 moles
<h3>Further explanation</h3>
The combustion of hydrocarbons with excess oxygen will produce carbon dioxide and water(CO₂+H₂O), whereas if there is not much oxygen, carbon monoxide and water(CO+H₂O) will be obtained.
The reaction coefficient in a chemical equation shows the mole ratio of the reacting compounds
Reaction (combustion of butane) :
<em>2C₄H₁₀+13O₂⇒8CO₂+10H₂O</em>
Butane reacts completely, then Butane is the limiting reactant and oxygen as the excess reactant, so the moles of Carbon dioxide are based on the butane moles as the limiting reactant.
moles of butane - C₄H₁₀ = 5 moles
From the reaction, the mol ratio of C₄H₁₀ and CO₂ : 2 : 8, so mol CO₂ :
