Yes. A regular polygon is equilateral and equiangular; an equilateral triangle is both equilateral and equiangular, so a triangle can be a regular polygon.
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Answer:
C. 60 ft
Step-by-step explanation:
5 ft woman / 2 ft shadow
? ft antenna / 24 ft shadow
proportion time!
25*5 = 120
120/2 = 60
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Answer:
Step-by-step explanation:
<u>Given GP with </u>
<u>Let the common difference is r, then</u>
<u>Solve for r and then a₁:</u>
- 4r = 7 ⇒ r = 7/4
- a₁(7/4)³ = 4
- a₁ = 4*(4/7)³ = 4⁴/7³ = 256/343
If d₁ and d₂ are the lengths of the diagonals, the area is given by
.. A = (1/2)*d₁*d₂
.. A = (1/2)*(12 in)*(16 in)
.. A = 96 in²
If b is the base and h is the height, the area is given by
.. A = b*h
We know the values of A and b, so
.. 96 in² = (10 in)*h
.. (96 in²)/(10 in) = h = 9.6 in
The height is 9.6 in.
Answer:
2(Jill) - 20 + (Jill) = 205
3(Jill) = 225
(Jill) = 75
(Jack) = 2(75) - 20 => 150 - 20 = 130
Jill= 75
Jack= 130
Step-by-step explanation: