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Blababa [14]
3 years ago
10

What does google search console report​

Computers and Technology
1 answer:
Natali [406]3 years ago
4 0

Answer:

Search console data

Explanation:

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A testing lab wishes to test two experimental brans of outdoor pain long each wiil last befor fading . The testing lab makes six
Simora [160]

Answer:

The answer is "\bold{Brand \ A \ (35, 350, 18.7) \ \ Brand \ B \ (35, 50, 7.07)}"

Explanation:

Calculating the mean for brand A:

\to \bar{X_{A}}=\frac{10+60+50+30+40+20}{6}  =\frac{210}{6}=35

Calculating the Variance for brand A:

\sigma_{A}^{2}=\frac{\left ( 10-35 \right )^{2}+\left ( 60-35 \right )^{2}+\left ( 50-35 \right )^{2}+\left ( 30-35 \right )^{2}+\left ( 40-35 \right )^{2}+\left ( 20-35 \right )^{2}}{5} \\\\

     =\frac{\left ( -25 \right )^{2}+\left ( 25  \right )^{2}+\left ( 15\right )^{2}+\left ( -5 \right )^{2}+\left ( 5 \right )^{2}+\left ( 15 \right )^{2}}{5} \\\\ =\frac{625+ 625+225+25+25+225}{5} \\\\ =\frac{1750}{50}\\\\=350

Calculating the Standard deviation:

\sigma _{A}=\sqrt{\sigma _{A}^{2}}=18.7

Calculating the Mean for brand B:

\bar{X_{B}}=\frac{35+45+30+35+40+25}{6}=\frac{210}{6}=35

Calculating the Variance for brand B:

\sigma_{B} ^{2}=\frac{\left ( 35-35 \right )^{2}+\left ( 45-35 \right )^{2}+\left ( 30-35 \right )^{2}+\left ( 35-35 \right )^{2}+\left ( 40-35 \right )^{2}+\left ( 25-35 \right )^{2}}{5}

    =\frac{\left ( 0 \right )^{2}+\left ( 10 \right )^{2}+\left ( -5 \right )^{2}+\left (0 \right )^{2}+\left ( 5 \right )^{2}+\left ( -10 \right )^{2}}{5}\\\\=\frac{0+100+25+0+25+100}{5}\\\\=\frac{100+25+25+100}{5}\\\\=\frac{250}{5}\\\\=50

 Calculating the Standard deviation:  

\sigma _{B}=\sqrt{\sigma _{B}^{2}}=7.07

4 0
3 years ago
Write a program that reads an integer, a list of words, and a character. The integer signifies how many words are in the list. T
kompoz [17]

Answer:

I can't read that pls reformat, or take picture.

Explanation:

3 0
3 years ago
A small grocery store has one checkout.You have been asked to write a program to simulate the grocery store as it checks out cus
Masteriza [31]

Answer:

Check the explanation

Explanation:

PYTHON CODE :

#import random function

from random import randint

#class Queue declaration

class Queue:

#declare methods in the Queue

def __init__(self):

self. items = []

def isEmpty(self):

return self. items == []

def enqueue(self, item):

self.items. insert(0, item)

def dequeue(self):

return self. items. pop()

def size(self):

return len(self. items)

def getInnerList(self):

return self.items

#This is customer Queue

class Customer:

#declare methods

def __init__(self,n):

self.numberOfItems=n

def __str__(self):

return str(self. numberOfItems)

def getNumberOfItems(self):

return self. numberOfItems

#This is expresscheker customer queue

class Expresschecker:

def __init__(self,n):

self.numberOfItems=n

def __str__(self):

return str(self. numberOfItems)

def getNumberOfItems(self):

return self. numberOfItems

#Returns random checkout time, based on number of items

def checkOut(Expresschecker):

items = Expresschecker. getNumberOfItems()

if items <= 10:

return randint(2, 5)

if items <= 20:

return randint(6, 9)

return randint(10, 14)

#Initiate queue for the Expresschecker

Expresschecker = Queue()

#declare total customers

totalcheckoutCustomers = 10

#express Customers shopping..

for i in range(totalcheckoutCustomers):

#Each putting Between 1 to 25 items

randomItemsQty = randint(1, 25)

customer = Customer(randomItemsQty)

#Getting into queue for checkout

Expresschecker. enqueue(customer)

#====Now all express Customers having

#random qty of items are in Queue======

#intial time

totalTime=0

#define the size of the queue

totalcheckoutCustomers = Expresschecker. size()

#using for-loop until queue is empty check out

#the items in the express cheker queue

while not(Expresschecker. isEmpty()):

totalTime+=randint(1,5)

#Picking a customer

expresscustomer = Expresschecker. dequeue()

#Processing the customer

timeTaken = checkOut(expresscustomer)

#add the time for each custimer

totalTime+=timeTaken

#compute average waiting time

averageWaitingTime = totalTime/totalcheckoutCustomers

#display the average waiting time

print("Average waiting time for the express customer queue is "

+str(averageWaitingTime)+" minutes ")

print("Remaining Custimers in the express customer Queue is: ",

Expresschecker. size())

#Returns random checkout time, based on number of items

def checkOut(customer):

items = customer. getNumberOfItems()

if items <= 10:

return randint(1, 5)

if items <= 20:

return randint(6, 10)

return randint(11, 15)

#in

customersQueue = Queue()

totalCustomers = 20 #Change number of customers here

#Customers shopping..

for i in range(totalCustomers):

#Each putting Between 1 to 25 items

randomItemsQty = randint(1, 25)

customer = Customer(randomItemsQty)

#Getting into queue for checkout

customersQueue. enqueue(customer)

#====Now all Customers having random qty

#of items are in Queue======

totalTime=0

totalCustomers = customersQueue. size()

while not(customersQueue. isEmpty()):

totalTime+=randint(1,5)

#Picking a customer

customer = customersQueue. dequeue()

#Processing the customer

timeTaken = checkOut(customer)

totalTime+=timeTaken

#Result=============================

averageWaitTime = totalTime/totalCustomers

print("Average wait time for the customer queue is

"+str(averageWaitTime)+" minutes ")

print("Remaining Customers in the customer Queue is:

",customersQueue. size())

5 0
3 years ago
Using bearings will cause more friction. Group of answer choices True False
Olegator [25]

Answer:

False

Explanation:

6 0
3 years ago
A group of N stations share a 56-kbps pure ALOHA channel. Each station outputs a 1000-bit frame on average once every 100 sec, e
Sunny_sXe [5.5K]

Explanation:

Here, in the given statement, maximum flow capacity of the ALOHA channel = 18.4% = 0.184

Then, the stations N share 56 kbps

And, the channel rate = 0.184*56 = 10.304 kbps.  

Then, the outputs of the wach stations is 1000-bit frames/100 sec

\therefore, the output of the bits/ sec by each stations = \frac{1000}{100} bits/sec = 10 bits/sec

So, The output of the N stations is 10 bits/sec on the channel that having 10.304kb/sec

Finally, N = \frac{(10.304 \times 10^{3})}{10} = 1030 stations

3 0
3 years ago
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