Answer:
1.20 V
Explanation:
Here Pb undergoes oxidation by loss of electrons, thus act as anode. Bromine undergoes reduction by gain of electrons and thus act as cathode.
Where both 
are standard reduction potentials.
Given,
![E^0_{[Pb^{2+}/Pb]}= -0.13\ V](https://tex.z-dn.net/?f=E%5E0_%7B%5BPb%5E%7B2%2B%7D%2FPb%5D%7D%3D%20-0.13%5C%20V)
![E^0_{[Br_2/Br^{-}]}=+1.07\ V](https://tex.z-dn.net/?f=E%5E0_%7B%5BBr_2%2FBr%5E%7B-%7D%5D%7D%3D%2B1.07%5C%20V)
![E^0=E^0_{[Br_2/Br^{-}]}- E^0_{[Pb^{2+}/Pb]}](https://tex.z-dn.net/?f=E%5E0%3DE%5E0_%7B%5BBr_2%2FBr%5E%7B-%7D%5D%7D-%20E%5E0_%7B%5BPb%5E%7B2%2B%7D%2FPb%5D%7D)
Answer:
Ice is less dense than water because of the way it forms a hexagonal crystalline structure. Each water molecule consists of two hydrogen atoms bonded to the bottom of an oxygen atom. ... In the winter, temperatures in a lake get close enough to freezing that the colder water is less dense and floats to the top
Explanation:
Answer:
the change of occurs between200and750 is less than 100°C ans will be same and the answer is to calculate
The conversion that can be used is 1 cm³ / mL
After multiplying by this conversion, we get:
1000 mL * (1 cm³ / mL) = 1000 cm³
Next, we may convert directly from cm³ to m³ by:
1 m = 100 cm
1 m³ = 100³ cm³
Using this conversion, we get the volume in m³ to be:
0.001 m³
A) cesium chloride
B) barium oxide
C) potassium sulfide
D) beryllium chloride
E) hydrogen bromide
F) aluminum fluoride
