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Dafna1 [17]
4 years ago
14

3. An adult rhino is 1350 kilograms. What is its mass in micrograms? Please write your answer in correct Scientific Notation. Mi

crograms
Chemistry
1 answer:
Radda [10]4 years ago
3 0

Answer:

1.35×10¹² μg

Explanation:

Mass (Kg) = 1350 Kg

Mass (μg) =?

Thus, we can obtain the mass of the adult rhino in micrograms (μg) by converting 1350 Kg to microgram (μg) as follow:

1 Kg = 1×10⁹ μg

Therefore,

1350 Kg = 1350 kg / 1 kg × 1×10⁹ μg

1350 Kg = 1.35×10¹² μg

Therefore, 1350 Kg is equivalent to 1.35×10¹² μg.

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What is the energy of the photons of a laser with a frequency of 5.75 x 10^12 Hz? (Hint: Remember to round your answer to the lo
Simora [160]

Answer:

E = 3.81×10 ⁻²¹ J

Explanation:

Given data:

Frequency of photon = 5.75 ×10¹² Hz

Plancks constant = 6.626 ×10⁻³⁴ Js

Energy of photon = ?

Solution:

E = h×f

E = 6.626 ×10⁻³⁴ Js ×  5.75 ×10¹² s⁻¹

E = 38.1×10 ⁻²² J

E = 3.81×10 ⁻²¹ J

8 0
3 years ago
A non-metallic atom(at.no. 9) forms a molecule of the same,containing a single covalent bond. give reason
bezimeni [28]
They are so may forms
4 0
3 years ago
Which statement defines rate-determining step in a chemical reaction?
PilotLPTM [1.2K]
The correct response would be A. The slowest step that determines the speed(rate) of the overall reaction.
4 0
4 years ago
Read 2 more answers
The half-life of strontium-90 is 28.1 years. Calculate the percent of a strontium sample left after 100 years.
Aliun [14]

Answer:

  • Option 4. 8.5%

Explanation:

The<em> half-life </em>time of a radiactive isotope (radioisotope) is a constant value, meaning that the amount of the radioisotope that decays will be (1/2) raised to the number of half-lives passed.

Naming A₀ the initial amount to the radioisotope, you can build this table to find the amount left.

Number of half-lives           amount of radiosotope left

       0                                              A₀

       1                                               (1/2) × A₀

       2                                              (1/2)×(1/2)×A₀ = (1/2)² × A₀

       3                                              (1/2)³ ×A ₀

       4                                              (1/2)⁴ × A₀

       n                                              (1/2)ⁿ × A₀

Now calculate the number of half-lives the strontium-90 sample has passed after 100 years:

  • n = 100 years / 28.1 years ≈ 3.5587

Hence, the amount of strontium-90 is:

(\frac{1}{2})^{3.5587}A_0=0.08486A_0

In percent, that is:

(0.08486A_0/A_0).100=8.486%

Rounding to two significant figures, that is 8.5%.

<u>Conclusion</u>: <em>The percent of strontium-90 left after 100 yeaers is 8.5% </em>(choice number 4).

6 0
3 years ago
Calculate the grams of NaCl (5.5 by mass) in 250 grams of commercial bleach solution
Naddik [55]

Mass of NaCl L 13.75 g

<h3>Further explanation</h3>

Given

The solution of 5.5% by mass

mass of commercial bleach solution : 250 g

Required

mass of NaCl

Solution

Percent mass (% w/w) = percent mass of solute in 100 g mass of solution

Solution = solute + solvent

Solute = NaCl

Solution = Commercial bleach

Can be formulated :

\tt \%mass(w/w)=\dfrac{mass~solute}{mass~solution}\times 100\%

Input given values in formula :

\tt \%mass=\dfrac{mass~NaCl}{mass~commercial~bleach}\times 100\%\\\\5.5\%=\dfrac{mass~NaCl}{250}\times 100\%\\\\mass~NaCl=\boxed{\bold{13.75~g}}

7 0
3 years ago
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