Answer:
Final volume 30.513 L.
Explanation:
According to general gas equation:
P₁V₁/T₁ = P₂V₂/T₂
Given data:
Initial volume = 17 L
Initial pressure = 2.3 atm
Initial temperature = 299 K
Final temperature = 350 K
Final volume = ?
Final pressure = 1.5 atm
Solution:
P₁V₁/T₁ = P₂V₂/T₂
V₂ = P₁V₁ T₂/ T₁ P₂
V₂ = 2.3 atm × 17 L × 350 K / 299 K × 1.5 atm
V₂ = 13685 atm .L. K / 448.5 K . atm
V₂ = 30.513 L
Answer:
The new pressure of the gas comes out to be 400 KPa.
Explanation:
Initial volume of gas = V =
Initial pressure of gas = P = 120 KPa
Final volume of gas = V' =
Assuming temperature to be kept constant.
Assuming final pressure of the gas to be P' KPa

New pressure of gas = 400 KPa
Flamability boiling point color