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Neporo4naja [7]
4 years ago
9

____________ is a colorless, odorless gas that forms when fuels are not completely burned.

Chemistry
2 answers:
andrezito [222]4 years ago
7 0

Explanation:

Carbon monoxide is a toxic and flammable gas which is also colorless. Chemical formula of carbon monoxide is CO.

This gas is produced upon incomplete combustion of carbon.

For example, C(s) + \frac{1}{2}O_{2}(g) \rightarrow CO(g)

Therefore, we can conclude that carbon monoxide is a colorless, odorless gas that forms when fuels are not completely burned.

-Dominant- [34]4 years ago
3 0
Your answer is Carbon monoxide
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\The specific heat of aluminum is 0.21 cal g°C . How much heat is released when a 10 gram piece of aluminum foil is taken out of
DiKsa [7]

<u>Answer: </u>The amount of heat released is 84 calories.

<u>Explanation: </u>

The equation used to calculate the amount of heat released or absorbed, we use the equation:

Q= m\times c\times \Delta T

where,

Q = heat gained  or released = ? Cal

m = mass of the substance = 10g

c = specific heat of aluminium = 0.21 Cal/g ° C

Putting values in above equation, we get:

\Delta T={\text{Change in temperature}}=(10-50)^oC=-40^oC  

Q=10g\times 0.21Cal/g^oC\times-40^oC

Q = -84 Calories

Hence, the amount of heat released is 84 calories.

6 0
3 years ago
Is baking soda is dissolved in vinegar and bubbles appear a chemical change?
nydimaria [60]
Yes baking soda is dissolved in vinegar and bubbles appear is a CHEMICAL CHANGE .
8 0
4 years ago
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Explain how astronomers use spectrographs to identify the composition of a star.
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4 0
3 years ago
3. A 3.455-g sample of a mixture was analyzed for barium ion by adding a small excess of sulfuric acid to an aqueous solution of
erik [133]

Answer:

Ba\ percentage\ in\ Mass=4.8\%

Explanation:

From the question we are told that:

Mass of mixture m=3.455g

Mass of Barium m_b=0.2815g

Equation of Reaction is given as

Ba2+ + H2SO4 => BaSO4 + 2 H+

Generally the equation for Moles of Barium  is mathematically given by

Since

 Moles of Ba^{2+} = Moles of BaSO_4

Therefore

 Moles of Ba^{2+}  = \frac{mass}{molar mass of BaSO4}  

 Moles of Ba^{2+} = \frac{0.2815}{233.39}= 0.0012061 mol

Generally the equation for Mass of Barium  is mathematically given by

 Mass\ of\ Ba^{2+} = Moles * Molar mass of Ba^{2+}  

 Mass\ of\ Ba^{2+} = 0.0012061 * 137.33 = 0.1656 g

Therefore

 Ba\ percentage\ in\ Mass = mass of Ba^{2+}/mass of sample * 100%    

 Ba\ percentage\ in\ Mass= \frac{0.1656}{ 3.455 }* 100%

 Ba\ percentage\ in\ Mass=4.8\%

8 0
3 years ago
How do you do empirical formula
mihalych1998 [28]

Answer:

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Explanation:

Step 1: Obtain the mass of each element present in grams. Element % = mass in g = m.

Step 2: Determine the number of moles of each type of atom present. ...

Step 3: Divide the number of moles of each element by the smallest number of moles. ...

Step 4: Convert numbers to whole numbers.

7 0
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