Answer:
The half reaction occurring at this electrode will be given as:

Explanation:
In electrochemical cell reduction occurs at anode.
But the gold wire is connected to the positive terminal of the battery which means that gold wire will act as a cathode nad reduction will take place
The half reaction occurring at this electrode will be given as:

As a diprotic acid, the H₂SeO₃ can ionize by step. First step is H₂SeO₃ =(reversible reaction) H⁺ + HSeO₃⁻. And second step is HSeO₃⁻ =(reversible reaction) H⁺ +SeO₃ ²⁻.
<span>The product would be :
H3O+ Benzaldehyde -----> C6H5CHO.
It will form a neutral molecule. So the charge is neutral.
I hope it helped.</span>
Answer:
See explaination
Explanation:
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