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Leno4ka [110]
3 years ago
11

How many calories of heat are required to raise the temperature of 225g of water from 10.5°C to 43.7°C

Chemistry
1 answer:
Luda [366]3 years ago
8 0
This the answer to the question you asked:)

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Which of the following acts as a catalyst in your body? A. Sweat B. Enzymes C. Blood cells D. Sugar
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4 years ago
Put these numbers from greatest to least precision<br> 0.10 g/mL <br> 0.0447g/mL <br> 0.0700g/mL
horrorfan [7]
I am going to go with,

0.10 g/mL
0.0700 g/mL
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3 years ago
Five kilograms of liquid carbon tetrachloride undergo a mechanically reversible, isobaric change of state at 1 bar during which
Drupady [299]

Answer:

Explanation:

From the information given:

Mass of carbon tetrachloride = 5 kg

Pressure = 1 bar

The given density for carbon tetrachloride = 1590 kg/m³

The specific heat of carbon tetrachloride =  0.84 kJ/kg K

From the composition, the initial volume of carbon tetrachloride will be:= \dfrac{5 \ kg }{1590 \ kg/m^3}

= 0.0031 m³

Suppose \beta is independent of temperature while pressure is constant;

Then:

The change in volume can be expressed as:

\int ^{V_2}_{V_1} \dfrac{dV}{V} =\int ^{T_2}_{T_1} \beta dT

In ( \dfrac{V_2}{V_1})  = \beta (T_2-T_1)

V_2 = V_1 \times exp (\beta (T_2-T_1))

V_2 = 0.0031 \ m^3  \times exp  (1.2 \times 10^{-3} \times 20)

V_2 = 0.003175 \ m^3

However; the workdone = -PdV

W = -1.01 \times 10^5 \ Pa \times ( 0.003175 m^3 - 0.0031 \ m^3)

W = - 7.6 J

The heat energy Q = Δ h

Q = mC_p(T_2-T_1)

Q = 5 kg \times 0.84 \ kJ/kg^0 C \times 20

Q = 84 kJ

The internal energy is calculated by using the 1st law of thermodynamics; which can be expressed as;

ΔU = ΔQ + W

ΔU = 84 kJ + ( -7.6 × 10⁻³ kJ)

ΔU = 83.992 kJ

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3 years ago
How many atoms are in 1.50 moles of fluorine gas
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1.8x10^24 atoms is How many atoms are in 1.50 moles of fluorine gas
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