: A chemical process of decomposition involving the splitting of a bond by the addition of water.
However, Duncan has prepared ramen noodles so many times he does not need to measure the water carefully. If he happens to heat 0.850 ...
From the reactions, 1.04 g of H2 and 7.995 g of aluminum phosphate is produced.
<h3>What is stoichiometry?</h3>
The term stoichiometry has to do with the amount of substances that participates in a reaction.
For reaction 1;
Mg + 2HCl → MgCl₂ + H₂
Number of moles of Mg reacted = 12.5 g/24g/mol = 0.52 moles
If 1 mole of Mg produced 1 mole of H2
0.52 moles produces 0.52 moles of H2
Mass of H2 = 0.52 moles * 2 g/mol = 1.04 g
For reaction 2;
2Li3PO4 + Al2(SO4)3 → 3Li2SO4 + 2AIPO4
Number of moles of lithium phosphate = 7.5 g/116 g/mol = 0.065 moles
2 moles of Li3PO4 produced 2 moles of AIPO4
0.065 moles of Li3PO4 produced 0.065 moles of AIPO4
Mass of AIPO4 = 0.065 moles * 123 g/mol = 7.995 g
Learn more about stoichiometry:brainly.com/question/9743981
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Burning of oil,gases and coal are the antropogenic source of co2
Answer:1) Volume of
required is 55.98 mL.
2) 0.62577 grams of
is produced.
Explanation:

1) Molarity of 
Volume of 
Molarity of 
Volume of 


According to reaction, 1 mole of
reacts with 3 mole of
, then, 0.0041985 moles of
will react with:
moles of
that is 0.0125955 moles.


Volume of
required is 55.98 mL.
2)

Number of moles of
According to reaction, 3 moles of
gives 1 mole of
, then 0.004485 moles of
will give:
moles of
that is 0.001495 moles.
Mass of
=
Moles of
× Molar Mass of 
= 0.001495 moles × 418.58 g/mol = 0.62577 g
0.62577 grams of
is produced.