Answer:
Explanation:
A covalent compound is a compound formed by covalent bonds. A covalent bond is formed between two atoms where electrons are shared between the two atoms. This forms a molecule.
What determines whether two elements will form a covalent compound or not is the number of valence electrons present in each of the elements.
Fluorine will form a covalent compound with phosphorous because fluorine has 5 electrons in its outermost shell. It needs 3 more to become stable.
Phosphorous also has 5 valence electrons. It needs 3 more to become stable.
What happens is that 3 atoms of FLuorine combine with one atom of Phosphorus, sharing the valence electrons between themselves. This leads to the formation of the PF3 molecule.
Both the Phosphorous and the Fluorine are now stable.
A solution of K2SO4 and KCl is added to a solution of Ba(NO3)2. BaS0₄ (s) will precipitate out of this combined solution.
Molecular equation
K2SO4(aq) + Ba(NO3)2(aq) → BaSO4(s) + 2 KNO3(aq)?
This equation represents a double displacement (replacement) reaction, also called a metathesis reaction, in which the reactant ions exchange places to form new products. The general equation is:
A-B + C-D → A-D + C-B;
where A and C are cations, and B and D are anions.
Complete ionic equation: Includes all ions and the precipitate.
2K^+(aq) + SO4^2-(aq) + Ba^2+(aq) + 2[NO3]^-(aq) → 2K^+(aq) + 2[NO3]^- + BaSO4(s)
In an aqueous solution, precipitation is the process of transforming a dissolved substance into an insoluble solid from a super-saturated solution.
The solid formed is called the precipitate. In case of an inorganic chemical reaction leading to precipitation, the chemical reagent causing the solid to form is called the precipitant.
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Answer:
The answer to your question is below
Explanation:
Data
[HBr] = 0.045 M
[H⁺] = ?
[OH⁻] = ?
pH = ?
pOH = ?
Process
1.- Determine the [H⁺]
The [H⁺] is equal to the [HBr] then, [H⁺] = 0.045 M
2.- Determine the pH
pH = -log[H⁺]
-Substitution
pH = -log[0.045]
-Result
pH = 1.35
3.- Determine the pOH
Formula
pH + pOH = 14
-Solve for pOH
pOH = 14 - pH
-Substitution
pOH = 14 - 1.35
-Result
pOH = 12.65
4.- Determine the [OH⁻]
pOH = -log[OH⁻]
-Solve for [OH⁻]
[OH⁻] = antilog(-pOH)
-Substitution
[OH⁻] = antilog (-12.65)
-Result
[OH⁻] = 2.22 x 10⁻¹³