Answer:
Your number is -10
Hope this helps :)
Step-by-step explanation:
Let x be the number
Twice a number is 2x
Added to 7 means + 7 so 2x + 7
Is means =
2x+7=
At this point I have to assume you mean
"is the same as three subtracted from THE SAME number"
Otherwise, rather than a number, we end up with the
equation of a line....
2x + 7 = x - 3 subtract x from both sides
x + 7 = -3 subtract 7 from both sides
x = -10
Your number is -10
Check: 2x+7 = x-3
2(-10) + 7 = -10-3
-20+7 = -13
-13 = -13
The answer fits the parameters of the problem.
Answer:
yes , 33^2 + 56^2 = 65^2 and obtuse
Step-by-step explanation:
<h2><u>Question 3</u></h2>
make use of the Pythagoras theorem
which is :
c^2 = a^2 + b^2
where c is the hypotenuse.
now put the values in the equation
65^2 = 56^2 + 33 ^2
the answer is :
<u>yes , 33^2 + 56^2 = 65^2</u>
<u></u>
<h2><u>Question 4</u></h2>
<u />
note if :
c^2 = a^2 + b^2 ----------- right
c^2 < a^2 + b^2------------ acute
c^2 > a^2 + b^2------------- obtuse
hence :
16 + 30 > 38
therefore its : <u>obtuse </u>
I think they are called sides.
Answer:
Let's use the Pythagorean theorem!! I think there are two correct answers, right?
