Answer:
1) 46%
2) 0.07
3) 0.1148
4) 0.1372
Step-by-step explanation:
Total number of patients = 50
Total number of dogs = 7 + 4 + 5 + 5 + 2 = 23
Part 1)
The percentage of patients that were dogs = ![\frac{23}{50} \times 100 \% = 46\%](https://tex.z-dn.net/?f=%5Cfrac%7B23%7D%7B50%7D%20%5Ctimes%20100%20%5C%25%20%3D%2046%5C%25)
Thus, 46% of the patients were dogs.
So,
p =46% = 0.46
Part 2)
p = 0.46
n = 50
Using the values in the given formula, we get:
![S.E=\sqrt{\frac{0.46(1-0.46)}{50} }\\\\ S.E=0.07](https://tex.z-dn.net/?f=S.E%3D%5Csqrt%7B%5Cfrac%7B0.46%281-0.46%29%7D%7B50%7D%20%7D%5C%5C%5C%5C%20S.E%3D0.07)
Thus, the standard error is 0.07
Part 3)
Z-value for 90% confidence interval is 1.64. This value is found using z-table or can be found using online calculators.
Margin of error = z-value x S.E
Using the values, we can write:
Margin of error = 1.64 x 0.07
Margin of error = 0.1148
Thus margin of error for 90% confidence interval is 0.1148
Part 4)
Z-value for 95% confidence interval is 1.96
Margin of error = z-value x S.E
Using the values, we can write:
Margin of error = 1.96 x 0.07
Margin of error= 0.1372
Thus margin of error for 95% confidence interval is 0.1372