Answer:
The distance travelled when the brakes are applied, (x2 - x1) = (d - v₀t)
Acceleration of the car after brakes are applied = - [v₀²/(d - v₀t)]
Explanation:
The driver initially distance d, away from the can, travels a further distance of v₀t.
New distance of the driver from the can = (d - v₀t)
And it is said that the driver stops just before the can,
Hence, the distance travelled when the brakes are applied, x2 - x1 = (d - v₀t)
The acceleration after the application if the brakes is obtained from the equations of motion.
Distance travelled = (d - v₀t)
Initial velocity before the application of brakes = v₀ m/s
Final velocity = 0 m/s
acceleration = ?
√ ²
But we know acceleration is negative, since it is deceleration.
Using v₀² = 0 - 2a(d - v₀t)
a =- [v₀²/(d - v₀t)]
