If you start using 10.0 grams of NaHCO3 and excess of acetic acid, how many moles of CO2 can be formed? How many grams of CO2 ca
1 answer:
Answer:
Explanation:
Hello.
In this case, since the chemical reaction:
And 10.0 grams of sodium bicarbonate (molar mass = 84 g/mol) are reacting in a 1:1 mole ratio with the yielded carbon dioxide, those moles and grams turn out:
And the mass by considering the molar mass of carbon dioxide to be 44 g/mol:
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For this reaction to proceed, the following bond breaking should occur:
*one C-O bond* one H-Cl bond
After, the following bond formations should occur:*one C-Cl bond*one O-H bond
Now, add the bond energies for the respective bond energies which can be found in the attached picture. For bond formations, energy is negative. For bond breaking, energy is positive.
ΔHrxn = (1)(358) + (1)(431) + 1(-328) + 1(-463) =<em> -2 kJ</em>
*one C-O bond* one H-Cl bond
After, the following bond formations should occur:*one C-Cl bond*one O-H bond
Now, add the bond energies for the respective bond energies which can be found in the attached picture. For bond formations, energy is negative. For bond breaking, energy is positive.
ΔHrxn = (1)(358) + (1)(431) + 1(-328) + 1(-463) =<em> -2 kJ</em>
Answer: 3.5 moles of hydrogen gas will be produced.
Explanation:
The balanced chemical equation is:
As HCl gets completely used up, is the limiting reagent.
According to stoichiometry :
6 moles of produces = 3 moles of
Thus 7.0 moles of produces=
of
Thus 3.5 moles of hydrogen gas will be produced.