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nirvana33 [79]
3 years ago
9

Which one if the following are appropriate units for measuring volume

Chemistry
1 answer:
Temka [501]3 years ago
5 0
Volume is expressed in "cubic" as prefix of the material being measured. 

<span>In cement, it would be measured in cubic yards </span>
<span>In liquids in can be liters, gallons, ounces etc.. </span>
<span>That's my answer off the top.... </span>
<span>Norm </span>

<span>In SI, you use litres and derivatives (such as ml, kl, etc.) </span>
<span>In Imperial and US, the units are ounces, cups, pints, quarts, and gallons.</span>
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Arsenic does not have any valence electrons in the 3D orbital because​
pogonyaev

Answer:

3d orbital is completely filled.

Explanation:

5 0
3 years ago
What is a possible set of quantum numbers for the unpaired electron in the following electron configuration: [Ar] 3d10 4s2 4p5?
Bogdan [553]

Answer:E

Explanation:

The electron is expected to be in any of the 4p orbitals. For the 4p orbitals

n=4

l=1

ml=-1,0,1

ms=-1/2 or +1/2

All the ml and ms configurations are equiprobable hence the answer.

6 0
3 years ago
Is heat conductivity a physical or chemical property?
Lena [83]
Chemical property because heat is not electrical.
8 0
3 years ago
A 45.0-gram sample of copper metal was heated from 20.0°C to 100.0°C. Calculate the heat absorbed, in kJ, by the metal.
s2008m [1.1K]

Answer:

1.386 KJ

Explanation:

From the question given above, the following data were obtained:

Mass (M) of copper = 45 g

Initial temperature (T1) = 20.0°C

Final temperature (T2) = 100.0°C

Heat absorbed (Q) =..?

Next, we shall determine the change in temperature. This can be obtained as follow:

Initial temperature (T1) = 20.0°C

Final temperature (T2) = 100.0°C

Change in temperature (ΔT) =?

ΔT = T2 – T1

ΔT = 100 – 20

ΔT = 80 °C

Next, we shall determine the heat absorbed by the sample of copper as follow:

Mass (M) of copper = 45 g

Change in temperature (ΔT) = 80 °C

Specific heat capacity (C) of copper = 0.385 J/gºC

Heat absorbed (Q) =..?

Q = MCΔT

Q = 45 × 0.385 × 80

Q = 1386 J

Finally, we shall convert 1386 J to KJ. This can be obtained as follow:

1000 J = 1 KJ

Therefore,

1386 J = 1386 J × 1 KJ /1000 J

1386 J = 1.386 KJ

Thus, the heat absorbed by the sample of the sample of copper is 1.386 KJ.

5 0
2 years ago
A 0.4021-g sample of a purified organic acid was dissolved in water and titrated potentiometrically. A plot of the data revealed
Archy [21]

Answer:

The molar mass of the acid is 167.5 g/mol

Explanation:

A 0.4021-g sample of a purified organic acid was dissolved in water and titrated potentiometrically. A plot of the data revealed a single end point after 19.31 mL of 0.1243 M NaOH had been introduced. Calculate the molecular mass of the acid.

Step 1: Data given

Mass of the sample of a purified organic acid = 0.4021 grams

Molarity = 0.1243 M

Volume needed to reach the end point = 19.1 mL = 0.01931 L

Step 2: Calculate the number of moles NaOH

Moles NaOH = molarity NaOH  * volume

Moles NaOH = 0.1243 M * 0.01931 L

Moles NaOH = 0.00240 moles

Step 3: Calculate moles of the acid

We'll need 0.00240 moles of acid to neutralize 0.00240 moles of NaOH ( it's a single end point)

Moles acid = 0.00240 moles

Step 4: Calculate molar mass of the acid

Molar mass = mass / moles

Molar mass = 0.4021 grams / 0.00240 moles

Molar mass = 167.5 g/mol

The molar mass of the acid is 167.5 g/mol

6 0
3 years ago
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