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timofeeve [1]
3 years ago
11

Write a chemical equation that describes the dissolving of solid magnesium nitrate, Mg(NO3)2, in water.

Chemistry
2 answers:
serious [3.7K]3 years ago
7 0
<span>Given below is the chemical equation that describes the dissolving of solid magnesium nitrate, Mg(NO3)2, in water Mg(NO3)2(aq) → Mg2+(aq) + 2NO3-(aq)</span>
Leviafan [203]3 years ago
5 0

Answer:

Your answer is Mg(NO3)2, in water Mg(NO3)2(aq) → Mg2+(aq) + 2NO3-(aq)

Explanation:

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Three isotopes of argon occur in nature. Calculate the average atomic mass of argon given the following relative atomic masses a
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What kind of bond is ca-br
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Scientists often work on projects for a long time and fail to see sources of error in their research. Which process allows an ou
prohojiy [21]

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The correct approach is Option B (Peer Review).

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  • Rather made reference to someone as a scientific peer-review, it encourages the specialist who has not been essential to the study team to analyze the study objectively and pointed out everyone's mistakes. It serves as major self-regulation for scholars and aims to make the publishing process somewhat credible. Hence, the solution to this issue is Peer Examination.
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Other approaches do not apply to the example mentioned. Although the one mentioned is right.

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Explain what Happens at the saturation point when adding salt to water at room temperature.
lorasvet [3.4K]

Answer:

See below  

Step-by-step explanation:

You won't see much happening. The solution is saturated, so the salt will fall to the bottom of the container and sit there. It will not dissolve.

However, at the atomic level, Na⁺ and Cl⁻ ions are being pulled from the surface of the crystals and going into solution as hydrated ions. At other places, Na⁺ and Cl⁻ ions are returning to the surface of the crystals.

The process is

NaCl(s) ⇌ Na⁺(aq) + Cl⁻(aq)

The rates of the forward and reverse processes are equal, so you see no net change.

6 0
3 years ago
658 mL of 0.250 M HCl solution is mixed with 325 mL of 0.600 M HCl solution. What is the molarity of the resulting solution
Tju [1.3M]

The molarity of the resulting solution obtained by mixing 658 mL of 0.250 M HCl solution with 325 mL of 0.600 M HCl solution is 0.366 M

We'll begin by calculating the number of mole of HCl in each solution. This can be obtained as follow:

<h3>For solution 1:</h3>

Volume = 658 mL = 658 / 1000 = 0.658 L

Molarity = 0.250 M

<h3>Mole of HCl =?</h3>

Mole = Molarity x Volume

Mole of HCl = 0.250 × 0.658

<h3>Mole of HCl = 0.1645 mole</h3>

<h3>For solution 2:</h3>

Volume = 325 mL = 325 / 1000 = 0.325 L

Molarity = 0.6 M

<h3>Mole of HCl =?</h3>

Mole = Molarity x Volume

Mole of HCl = 0.6 × 0.325

<h3>Mole of HCl = 0.195 mole</h3>

  • Next, we shall determine the total mole of HCl in the final solution. This can be obtained as follow:

Mole of HCl in solution 1 = 0.1645 mole

Mole of HCl in solution 2 = 0.195 mole

Total mole = 0.1645 + 0.195

<h3>Total mole = 0.3595 mole</h3>

  • Next, we shall determine the total volume of the final solution.

Volume of solution 1 = 0.658 L

Volume of solution 2 = 0.325 L

Total Volume = 0.658 + 0.325

<h3>Total Volume = 0.983 L</h3>

  • Finally, we shall determine the molarity of the resulting solution.

Total mole = 0.3595 mole

Total Volume = 0.983 L

<h3>Molarity =?</h3>

Molarity = mole / Volume

Molarity = 0.3595 / 0.983

<h3>Molarity = 0.366 M</h3>

Therefore, the molarity of the resulting solution is 0.366 M

Learn more: brainly.com/question/25342554

3 0
3 years ago
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