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lora16 [44]
2 years ago
14

Solve the system of linear equations using linear combination.

Mathematics
2 answers:
lisov135 [29]2 years ago
8 0

Answer:

The answer is (1,7). Hope it helps

brilliants [131]2 years ago
6 0
3a + 6b = 45
2a - 2b = -12....multiply by 3
----------------
3a + 6b = 45
6a - 6b = - 36 ...(result of multiplying by 3)
---------------add
9a = 9
a = 1

3a + 6b = 45
3(1) + 6b = 45
3 + 6b = 45
6b = 45 - 3
6b = 42
b = 7

solution is : (1,7)
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For a sample of 100 students, the median number of text messages sent per day is 90, the first quartile is 78, and the third qua
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between 78 and 102 texts and more than 78 text messages.

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Read 2 more answers
The target temperature for a laboratory is 72° Fahrenheit. It
myrzilka [38]

The inequality |t - 72| ≤ 2 represents the target temperature for a laboratory is 72° Fahrenheit, and it can vary by up to 2° option (D) is correct.

<h3>What is inequality?</h3>

It is defined as the expression in mathematics in which both sides are not equal they have mathematical signs either less than or greater than, known as inequality.

The question is incomplete.

The complete question is in the picture, please find the attached picture.

We have:

The target temperature for a laboratory is 72° Fahrenheit. It can vary by up to 2°.

Target temperature = 72 degree Fahrenheit

It can vary by up to 2°. (the highest limit)

The temperature in the laboratory represented by t

Now,

inequality represents this situation is:

|t - 72| ≤ 2

Thus, the inequality |t - 72| ≤ 2 represents the target temperature for a laboratory is 72° Fahrenheit, and it can vary by up to 2° option (D) is correct.

Learn more about the inequality here:

brainly.com/question/19491153

#SPJ1

6 0
1 year ago
Given that the quadratic equation has equal roots (k^2-1)x^2-2kx-3k-1=0
Alik [6]

Answer:

(See explanation for further details)

Step-by-step explanation:

The real expression is:

(k^{2}-1)\cdot x{{2} - 2\cdot k \cdot x - 3\cdot k + 1 = 0

The general equation for the second-order polynomial is:

x = \frac{2\cdot k \pm \sqrt{4\cdot k^{2}-4\cdot (k^{2}-1)\cdot (-3\cdot k + 1)}}{k^{2}-1}

This condition must be observed for the case of a quadratic equation with equal roots:

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k^{2} + 3\cdot k^{3} - 3\cdot k - k^{2}-1 = 0

3\cdot k^{3} - 3\cdot k - 1 = 0

7 0
3 years ago
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