Answer:
Final Volume = 5.18 Liters
Explanation:
Initial Condition:
P1 = 789 mm Hg x (1/760) atm /mm Hg = 1.038 atm
T1 = 22° C = 273 + 22 = 295 K
V1 = 4.7 L
Final Condition:
P2 = 755 mm Hg x (1/760) atm /mm Hg = 0.99 atm
T2 = 37° C = 273 + 37 = 310 K
V2 = ?
Since, (P1 x V1) / T1 = (P2 x V2) / T2,
Therefore,
⇒ (1.038)(4.7) / 295 = (0.99)(V2) / 310
⇒ V2 = 5.18 L (Final Volume)
Answer:
The new volume of gas would be 30 L.
Explanation:
This is an example of a Combined Gas Laws problem.
Explanation:
Boiling is defined as a process in which vapor pressure of a liquid substance becomes equal to the atmospheric pressure.
During this change liquid and vapors remain in equilibrium and the equation for this change is as follows.
Therefore, when boiling takes place then average kinetic energy of particles in liquid phase equals to the average kinetic energy of particles in vapor phase.
Hence, we can increase the kinetic energy of particles in liquid phase by increasing the temperature because kinetic energy is directly proportional to temperature as follows.
K.E = 
Answer:
43 mole
Explanation:
Given data:
Number of atoms of Li = 2.6× 10²⁵ atoms
Number of moles = ?
Solution:
The given problem will solve by using Avogadro number.
It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance. The number 6.022 × 10²³ is called Avogadro number.
1 mole = 6.022 × 10²³ atoms
2.6× 10²⁵ atoms × 1 mole / 6.022 × 10²³ atoms
0.43 × 10² mole
43 mole
Answer:
Gravitational force is directly promotional to the mass
of both interacting objects.
Explanation:
More massive objects will attract each other with
a greater gravitional force. So as the mass of the
either objects increases the force of gravitational
attraction between them also increases.
