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3 years ago

Why does the sun appear to be the brightest star in the sky?

Chemistry

1 answer:

skelet666 [1.2K]3 years ago

3 0

Answer:

Explanation:

There are only 2 ways to explain this.

distance

and brightness caused by what it is burning.

A is true but it is not the explanation of why it is true.

B this is actually not true. Other stars would burn much more.

C It is not the largest star. In fact it is in the lower middle.

D is the answer. 93 million miles as these things go, is not every much.

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Our current model of a chemical bond is to think of it as an electrical interaction between what two parts of an atom

Nikitich [7]

Answer:

Explanation:

It involves the thinking of it as an electrical interaction between the positively charged part of an atom and the negatively charged part as well. Succinctly put, the interaction between the proton of an atom and the electron of an atom.

The relationship between these two sub atomic particles is one of the basis for many chemical bonding, and this is inclusive of all the bonds there exist. Hydrogen, Electrovalent and even Covalent bondings to mention but a few

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2 years ago

10) What are the four main spheres of planet?

Tomtit [17]

Answer:

the four main spheres of the earth are geosphere, hydrosphere, atmosphere and biosphere

Explanation:

geosphere consists of all rocks on Earth

atmosphere which are the gases that surrounds the earth

hydrosphere which is all the water on the earth

biosphere which are the living things on the earth

5 0

3 years ago

Mention any two uses of oxygen gas.

Elodia [21]

Answer:

steel, plastics

<h3>Explanation:</h3>

Hope it helps!

3 0

3 years ago

Oblicz masę tlenu, wiedząc, że wypełnia on pomieszczenie o rozmiarach 2m x 3.5m x 3m. Gęstość tlenu wynosi 1,249kg/m3 .

Tanzania [10]

Analiza Z drugiej zasady Newtona przyłożona siła wynosi 1 N F = ma = m (6 g) = (90 kg) (6x9,81 m / s) 5297 N I kg m / s?

8 0

2 years ago

A 50/50 blend of engine coolant and water (by volume) is usually used in an automobile's engine cooling system. If a car's cooli

Diano4ka-milaya [45]

Answer:

$\large \boxed{109.17 \, ^{\circ}\text{C}}$

Explanation:

Data:

50/50 ethylene glycol (EG):water

V = 4.70 gal

ρ(EG) = 1.11 g/mL

ρ(water) = 0.988 g/mL

Calculations:

The formula for the boiling point elevation ΔTb is

$\Delta T_{b} = iK_{b}b$

i is the van’t Hoff factor — the number of moles of particles you get from 1 mol of solute. For EG, i = 1.

1. Moles of EG

$\rm n = 0.50 \times \text{4.70 gal} \times \dfrac{\text{3.785 L}}{\text{1 gal}} \times \dfrac{\text{1000 mL}}{\text{1 L}} \times \dfrac{\text{1.11 g}}{\text{1 mL}} \times \dfrac{\text{1 mol}}{\text{62.07 g}} = \text{159 mol}$

2. Kilograms of water

$m = 0.50 \times \text{4.70 gal} \times \dfrac{\text{3.785 L}}{\text{1 gal}} \times \dfrac{\text{998 g}}{\text{1 L}} \times \dfrac{\text{1 kg}}{\text{1000 g}} = \text{8.88 kg}$

3. Molal concentration of EG

$b = \dfrac{\text{159 mol}}{\text{8.88 kg}} = \text{17.9 mol/kg}$

4. Increase in boiling point

$\rm \Delta T_{b} = iK_{b}b = 1 \times 0.512 \, \, ^{\circ}\text{C} \cdot kg \cdot mol^{-1} \, \times 17.9 \cdot mol \cdot kg^{-1} = 9.17 \, ^{\circ}\text{C}$

5. Boiling point

$\rm T_{b} = T_{b}^{\circ} + \Delta T_{b} = 100.00 \, ^{\circ}\text{C} + 9.17 \, ^{\circ}\text{C} = \mathbf{109.17 \, ^{\circ}C}\\\rm \text{The boiling point of the solution is $\large \boxed{\mathbf{109.17 \, ^{\circ}C}}$}$

7 0

3 years ago