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avanturin [10]
3 years ago
6

How many milligrams of sugar are in a teaspoon of sugar

Chemistry
1 answer:
grigory [225]3 years ago
6 0

Answer 2325 milligrams.

Explanation:The unit is abbreviated as tsp. Convert Milligrams (mg) to Teaspoons (tsp): 1 mg is approximately equal to 0.0002 tsps. One milligram is a relatively small quantity of table sugar A mere one-teaspoon of granulated sugar contains some 2325 milligrams. Yay wiki

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PLS HELP ME I HAVE TILL 12
MariettaO [177]

Answer:

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Explanation:

92.3 kPa - 1.82 kPa = 90.5 kPa

keep up your hope also corrected me if a am wrong in anyway! :)

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Describe the position of metal ,non metals and metollieds in perodic tables​
siniylev [52]
Non metals and metollids in periodic tables are the same how this helps ;)
4 0
3 years ago
Decide which element probably has a boiling point most and least similar to the boiling point of cesium.
natka813 [3]

Answer:

Take a look at the attachment below

Explanation:

Take a look at the periodic table. As you can see, Rubidium is the closest element to Cesium, and happens to have the closest boiling point to Cesium, with only a difference of about 30 degrees.

Respectively, you would think that fluorine should have the least similarity to Cesium with respect to it's boiling point, considering it is the farthest away from the element out of the 4 given. This is not an actual rule, there are no fixed trends of boiling points in the periodic table, there are some but overall the trends vary. However in this case fluorine does have the least similarity to Cesium with respect to it's boiling point, a difference of about 1,546.6 degrees.

<em>Hope that helps!</em>

5 0
3 years ago
3: Consider molecules of hydrogen (tiny ones) and oxygen (bigger ones) in a gas mixture. If they have the same average kinetic e
mezya [45]

Answer: Hydrogen molecules will have greatest average speed.

Explanation:

The formula for average speed is  :

\mu_{av}={\sqrt{\frac{8RT}{\pi\times M}}}

R = gas constant  

T = temperature  

M = Molecular Mass

Now putting all the values:

\frac{\nu_{H_2}}{\nu_{O_2}}=\sqrt{\frac{8RT}{\pi\times M_{H_2}}}/{\sqrt{\frac{8RT}{\pi\times M_{O_2}}}

\frac{\nu_{H_2}}{\nu_{O_2}}=\sqrt{\frac{16}{2}}

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8 0
3 years ago
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katrin [286]

Answer:

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Low pressure reduces the effect of the finite size of real particles by increasing the volume around each particle, and a high temperature gives enough kinetic energy to the particles to better overcome the attractions that exist between real particles. (Prevents sticking.)

In summary, real gases behave more like ideal gases when they are far away from a phase boundary, (condensation or freezing).

3 0
2 years ago
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