Answer:
0.07142 m/s in the opposite direction of the bullet
Explanation:
= Mass of rifle = 70 kg
= Mass of bullet = 0.01 kg
= Velocity of rifle
= Velocity of bullet = 500 m/s
As the momentum of the system is conserved

The recoil velocity of the rifle is -0.07142 m/s
The negative sign shows the opposite direction of the rifle.
Answer:
Given:
Fundamental frequency: 470Hz
T1:310k,T2:315k
Calculating velocity
Recall v=(331m/s)✓[T1/273k)
V=331✓(310/273)
V1=331*(1.0656)=352.72m/s
V2=331✓(315/273)=355.5m/s
Fundamental frequency=4L
F2=F1(V2/V1)
F2=470(355.5/352.72)=474.4Hz
Beat=[F2-F1]=474.4-470=4.4Hz
Explanation:
D. The period is a measure of how much time it takes for the bob to go back and forth once.
We will apply the equation:2as = v² - u²v = √(2as + u²)v = √(2 x 4 x 400 + 13²)v = 58 m/s
She is

kilometers away from her starting point