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Afina-wow [57]
3 years ago
5

What is the period of a pendulum?

Physics
2 answers:
Grace [21]3 years ago
8 0
D. The period is a measure of how much time it takes for the bob to go back and forth once.
ivanzaharov [21]3 years ago
4 0

Answer:

d)the time it takes for the bob to swing back and forth once

Explanation:

Time period of any object is defined as the time after which it can complete its one round of repetitive motion

So here in the back and forth motion of simple pendulum we know that it will move to and fro about its mean position and the total time to make its to and from motion is known as its time period

so here correct answer would be

d) the time it takes for the bob to swing back and forth once

for simple pendulum the formula of time period is given as

T = 2\pi \sqrt{\frac{L}{g}}

here we know

L = length of pendulum

g = acceleration due to gravity

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A police car is driving down the street with it's siren on. You are standing still on the sidewalk beside the street. If the fre
AleksandrR [38]

Answer:

A) 1568.60 Hz

B) 1437.15 Hz

Explanation:

This change is frequency happens due to doppler effect

The Doppler effect is the change in frequency of a wave in relation to an observer who is moving relative to the wave source

f_(observed)=\frac{(c+-V_r)}{(C+-V_s)} *f_(emmited)\\

where

C = the propagation speed of waves in the medium;

Vr= is the speed of the receiver relative to the medium,(added to C, if the receiver is moving towards the source, subtracted if the receiver is moving away from the source;

Vs= the speed of the source relative to the medium, added to C, if the source is moving away from the receiver, subtracted if the source is moving towards the receiver.

A) Here the Source is moving towards the receiver(C-Vs)

and the receiver is standing still (Vr=0) therefore the observed frequency should get higher

f_(observed)=\frac{C}{C-V_s} *f_(emmited)\\=\frac{343}{343-15}*1500\\ =1568.60 Hz

B)Here the Source is moving away the receiver(C+Vs)

and the receiver is still not moving (Vr=0) therefore the observed frequency should be lesser

f_(observed)=\frac{C}{C+V_s} *f_(emmited)\\=\frac{343}{343+15}*1500\\ =1437.15 Hz

3 0
3 years ago
a flashlight operates with a current of 3.0 a and a power of 4.5 W. what is the voltage of the flashlights battery?
Dafna11 [192]

Answer:

V=1.5V

Explanation:

p=I×V

4.5=3×V

v =  \frac{4.5}{3}

v =  \frac{3}{2}

v=1.5

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the engine won't start or it sputters when it should be running perfectly. if the gasoline is old and stale, it will have lost a portion of its volatility. the lighter components of the gasoline (remember, gasoline is a mixture of different hydrocarbons) have probably evaporated off or disappeared.
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Answer:

First Law

Explanation:

I learned this in 6th grade

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