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3 years ago

What is the period of a pendulum?

Physics

2 answers:

Grace [21]3 years ago

8 0

D. The period is a measure of how much time it takes for the bob to go back and forth once.

ivanzaharov [21]3 years ago

4 0

Answer:

d)the time it takes for the bob to swing back and forth once

Explanation:

Time period of any object is defined as the time after which it can complete its one round of repetitive motion

So here in the back and forth motion of simple pendulum we know that it will move to and fro about its mean position and the total time to make its to and from motion is known as its time period

so here correct answer would be

d) the time it takes for the bob to swing back and forth once

for simple pendulum the formula of time period is given as

$T = 2\pi \sqrt{\frac{L}{g}}$

here we know

L = length of pendulum

g = acceleration due to gravity

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a football is thrown upward at a 31° angle to the horizontal.the acceleration of gravity is 9.8m/s^2. To throw the ball a distan

mr Goodwill [35]

The ball's vertical position $y$ in the air at time $t$ is

$y=v_0\sin31^\circ\,t-\dfrac g2t^2$

The ball is at its original height when $y=0$ , which happens at

$v_0\sin31^\circ\,t-\dfrac g2t^2=\dfrac t2\left(2v_0\sin31^\circ-gt)=0$

$\implies t=0\text{ and }t=\dfrac{2v_0\sin31^\circ}g$

Meanwhile, the ball's horizontal position $x$ at time $t$ is

$x=v_0\cos31^circ\,t$

So when the ball reaches its original height a second time, the ball will have traveled a horizontal distance of

$x=\dfrac{2{v_0}^2\sin31^\circ\cos31^\circ}g=\dfrac{{v_0}^2\sin(2\cdot31^\circ)}g$

(which you might recognize as the formula for the range of a projectile)

To reach a distance of $x=77\,\rm m$ , the initial speed $v_0$ would be

$77\,\mathrm m=\dfrac{{v_0}^2\sin62^\circ}{9.8\,\frac{\rm m}{\mathrm s^2}}\implies v_0=29\dfrac{\rm m}{\rm s}$

7 0

3 years ago

#26 question

4vir4ik [10]

So, the time that taken for the astronaut to fall to the surface of the moon is <u>2.5 s.</u>

<h3>Introduction</h3>

Hi ! In this question, I will help you. In this question, you will learn about the fall time of the free fall motion. Free fall is a downward vertical motion without being preceded by an initial velocity. When moving in free fall, the time required can be calculated by the following equation:

$\sf{h = \frac{1}{2} \cdot g \cdot t^2}$

$\sf{\frac{2 \cdot h}{g} = t^2}$

$\boxed{\sf{\bold{t = \sqrt{\frac{2 \cdot h}{g}}}}}$

With the following condition :

t = interval of the time (s)
h = height or any other displacement at vertical line (m)
g = acceleration of the gravity (m/s²)

<h3>Problem Solving</h3>

We know that :

h = height = 5.00 m
g = acceleration of the gravity = 1.6 m/s²

What was asked :

t = interval of the time = ... s

Step by step :

$\sf{t = \sqrt{\frac{2 \cdot h}{g}}}$

$\sf{t = \sqrt{\frac{2 \cdot 5}{1.6}}}$

$\sf{t = \sqrt{6.25}}$

$\boxed{\sf{t = 2.5 \: s}}$

<h3>Conclusion</h3>

So, the time that taken for the astronaut to fall to the surface of the moon is 2.5 s.

Time that needed for hearing the splash of fallen rock in the well brainly.com/question/26485521
The speed of the object at a certain height (free fall motion) brainly.com/question/26377041
The relationship between acceleration and the change in velocity and time in free fall brainly.com/question/26486625

3 0

3 years ago

Consider a particle with initial velocity v⃗ that has magnitude 12.0 m/s and is directed 60.0 degrees above the negative x axis.

lina2011 [118]

Answer:

-6.0 m/s, 10.4 m/s

Explanation:

To find the x- and y- components, we have to apply the formulas:

$v_x = v cos \theta$