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3 years ago

What is the period of a pendulum?

Physics

2 answers:

Grace [21]3 years ago

8 0

D. The period is a measure of how much time it takes for the bob to go back and forth once.

ivanzaharov [21]3 years ago

4 0

Answer:

d)the time it takes for the bob to swing back and forth once

Explanation:

Time period of any object is defined as the time after which it can complete its one round of repetitive motion

So here in the back and forth motion of simple pendulum we know that it will move to and fro about its mean position and the total time to make its to and from motion is known as its time period

so here correct answer would be

d) the time it takes for the bob to swing back and forth once

for simple pendulum the formula of time period is given as

$T = 2\pi \sqrt{\frac{L}{g}}$

here we know

L = length of pendulum

g = acceleration due to gravity

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Acceleration is best defined as the rate of change of __________ of an object. A. position B. force C. speed D. velocity 2. Whic

Fittoniya [83]

Velocity!
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7 0

3 years ago

Read 2 more answers

A jetliner rolls down the runway with constant acceleration from rest, it reaches its take off speed of 250 km/h in 1 min. What

nlexa [21]

Answer:

Acceleration, $a=14970.05\ km/h^2$

Explanation:

Given that,

Initially, the jetliner is at rest, u = 0

Final speed of the jetliner, v = 250 km/h

Time taken, t = 1 min = 0.0167 h

We need to find the acceleration of the jetliner. The mathematical expression for the acceleration is given by :

$a=\dfrac{v-u}{t}$

$a=\dfrac{250}{0.0167}$

$a=14970.05\ km/h^2$

So, the acceleration of the jetliner is $14970.05\ km/h^2$ . Hence, this is the required solution.

3 0

4 years ago

A uniform disk is constrained to rotate about an axis passing through its center and perpendicular to the plane of the disk. If

katrin2010 [14]

A uniform disk is constrained to rotate about an axis passing through its center and perpendicular to the plane of the disk. If the disk starts from rest and is then brought in contact with a spinning rubber wheel, we observe that the disk gradually begins to rotate too. If after 35 s of contact with this spinning rubber wheel, the disk has an angular velocity of 4.0 rad/s, find the average angular acceleration that the disk experiences. (Assume the positive direction is in the initial direction of rotation of the disk. Indicate the direction with the sign of your answer.)

Assume after 35 s of contact with this spinning rubber wheel, the disk has an angular velocity of 11.0 rad/s.

Answer:

385 rad

Explanation:

The expression for the angular acceleration of a disk that is in contact with a spinning wheel can be given as:

$\alpha = \frac{\delta \omega}{\delta t}$