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Aleks [24]
4 years ago
10

If the income elasticity for computers is 1.2, and incomes increase by 10%, the demand for computers, using one decimal place an

d the negative sign if necessary, will increase by _____%.
Computers and Technology
1 answer:
yarga [219]4 years ago
7 0

Answer:

The answer is "12.0%".

Explanation:

Economically, price elasticity makes a clear distinction between a consumer's production and a consumer's earnings.  

  • In this question, income elasticity is given that is "1.2", and incomes increase percentage is given, that is 10%.
  • The total income elasticity is in percentage is 1.2 \times 10 \% \ = 12.0\  \%.
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postnew [5]

Answer:

Complete code is given below:

Explanation:

import java.io.BufferedReader;

import java.io.FileNotFoundException;

import java.io.FileReader;

import java.io.IOException;

import java.util.Arrays;

import java.util.Scanner;

public class ArrayCalcs {

private int size;

String [] parts =null;

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try{

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String line = br.readLine();

int count = 0;

while (line != null) {

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for( String w : parts)

{

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}

line = br.readLine();

}

size=count;

arr=new double[size];

for(int i=0;i<size;i++){

arr[i]=Double.parseDouble(parts[i]);

}

// System.out.println(count);

// System.out.println(Arrays.toString(parts));

System.out.println(Arrays.toString(arr));

} catch (FileNotFoundException ex){

System.out.println("This file does not exist");

} catch (IndexOutOfBoundsException e){

System.out.println("Thie file has more than 7 lines");}

catch (IOException e) {

System.out.println(e.getMessage());

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public double getTotal(){

double sum=0.0;

for(double d:arr){

sum=sum+d;

}

return sum;

}

public double getAverage(){

double avg=getTotal()/arr.length;

return avg;

}

public double getHighest(){

double high=arr[0];

for(int i=0;i<arr.length-1;i++){

if(arr[i] > high)

high = arr[i];

}

return high;

}

public double getLowest(){

double low=arr[0];

for(int i=0;i<arr.length-1;i++){

if(arr[i] < low)

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}

return low;

}

public static void main(String[] args) {

Scanner s = new Scanner(System.in);

System.out.println("Enter file name:");

String file=s.next();

ArrayCalcs ac=new ArrayCalcs();

ac.readFile(file);

System.out.println(" Highest Element: "+ac.getHighest());

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4 0
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Answer:

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2 years ago
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