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Anastasy [175]
3 years ago
10

Ohm’s law describes the relationship between which quantities?

Chemistry
2 answers:
olga55 [171]3 years ago
8 0

Answer: The quantities are Voltage, Current and Resistance.

Explanation: Ohm's Law is the law which directly relates Current with Voltage.

This law states that the current passing through two points of a conductor is directly proportional to the potential difference across the two points.

Mathematically,

V\propto I

Removing the proportionality sign by adding a constant Resistance, 'R'

V=IR

where, V = Potential difference

I = Current

R = Resistance

Hence, the quantities which are related in this law are Current, Voltage and Resistance.

poizon [28]3 years ago
4 0
Current, resistance and voltage. 
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A) What is the maximum number of grams of nickel bromide that can be produced from the reaction of 67.8 g of nickel with 37.3 g
svetoff [14.1K]

Answer:

The answer to your question is a) 51.07 g of NiBr₂   b) Nickel, 54 g

Explanation:

Data

mass of NiBr₂ = ?

mass if Ni = 67.8 g

mass of Br = 37.3 g

Balanced chemical reaction

                Ni  +  Br₂   ⇒   NiBr₂

Process

1.- Find the atomic mass of the reactants and the molar mass of the product

Ni = 59 g

Br = 79.9 x 2 = 159.8 g

NiBr₂ = 59 + 159.8 = 218.8 g

2.- Find the limiting reactant

theoretical yield  Ni/Br₂ = 59/159.8 = 0.369

experimental yield Ni/Br₂ = 67.8/37.3 = 1.81

The limiting reactant is Bromine because the experimental yield was lower than the theoretical yield.

3.- Calculate the mass of NiBr₂

                    159.8 g of Br₂ --------------- 218.8 g of NiBr₂

                      37.3 g of Br₂ --------------  x

                          x = (37.3 x 218.8) / 159.8

                          x = 8161.24/159.8

                          x = 51.07 g of NiBr₂

4.- Find the excess reactant

The excess reactant is Nickel

                59 g of Ni ---------------- 159.8 g of Br₂

                  x               ----------------  37.3 g of Br₂

                            x = (37.3 x 59)/159.8

                            x = 2200.7/159.8

                            x = 13.77 g of Ni

Excess Ni = 67.8 - 13.77

                 = 54 g

5 0
3 years ago
Taxonomic classification is a process of science that organizes living organisms by their structure, function, and relationships
DiKsa [7]

D) The broadest group of organization is known as the domain.

8 0
3 years ago
The weathered debris in deserts consists mainly of
vampirchik [111]

Answer;

C. unchanged rock and mineral fragments

Explanation;

A large number of landforms and features found in desert environments are formed as the result of weathering. Weathering is defined as the breakdown and deposition of rocks by weather acting in situ

The two main types of weathering which occur in deserts are Mechanical weathering, which is the disintegration of a rock by mechanical forces that do not change the rock's chemical composition and Chemical weathering, which is the decomposition of a rock by the alteration of its chemical composition.

By contrast much of the weathered debris in deserts has resulted from mechanical weathering. Chemical weathering, however, is not completely absent in deserts. Over long time spans,clays and thin soils do form.


7 0
3 years ago
Read 2 more answers
How does a tree get energy?
Snezhnost [94]
Your answer is B. It gets energy from the Sun.
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6 0
2 years ago
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The specific rotation of (S)-2-butanol is +13.5. If 0.119 g of its enantiomer is dissolved in 10.0 mL of ethanol and
larisa86 [58]

Answer:

+15.8°

Explanation:

The formula for the observed rotation (α) of an optically active sample is

α = [α]<em>lc </em>

where

<em>l</em> = the cell path length in decimetres

<em>c</em> = the concentration in units of g/100 mL

[α] = the specific rotation in degrees  

1. Convert the concentration to units of g/100 mL

c = \frac{\text{0.119 g}}{\text{10.0 mL}} \times \frac{10 }{10 } =\frac{\text{1.19 g}}{\text{100 mL}}

2. Calculate the observed rotation

\alpha = (+13.3 ^{\circ}) \times 1.19 \times 1 = +15.8^{\circ}

7 0
3 years ago
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