The answer:
all that we search for is the number of mole of HCl and the number of mole of C2H6O
M(HCl) = 5.5g/ mole of HCl , so mole of HCl = 5.5/M(HCl), where M(HCl) is the molar mass.
M(HCl) = 1+ 36.5= 37.5
moles of HCl = 5.5/37.5=0.14
M(C2H6O) = 200g / moles of C2H6O, so moles of C2H6O=200g / M(C2H6O)
M(C2H6O)= 2x12+ 6 + 16=46,
moles of C2H6O=200g / 46 =<span>4.35 </span><span> moles
</span>
the sum of the moles is 0.14 + <span>4.35 </span> = 4.501 moles
finally, <span>The mole fraction of hcl in a solution prepared by dissolving 5.5 g of hcl in 200 g of c2h6o is 0.031
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because it can be found by 0.14 / 4.501= 0.031
Carbocation
I guess pls tell me if it wrong
Answer:
17,890 J
Explanation:
The amount of heat released by a gaseous substance when it condenses is given by the formula

where
n is the number of moles of the substance
is the latent heat of vaporization
The formula can be applied if the substance is at its vaporization temperature.
In this problem, we have:
n = 0.440 mol is the number of moles of steam
is the latent heat of vaporization of water
And the steam is already at 100C, so we can apply the formula:
