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hodyreva [135]
3 years ago
14

Why is it easier to deprotonate alkynes compared to alkanes and alkenes?​

Chemistry
1 answer:
8090 [49]3 years ago
4 0

Answer:

The acetylinic hydrogen atom is more acidic than the olefinic hydrogen atoms or hydrogen atoms attached to alkanes.

Explanation:

The acidity of a terminal alkyne is as a result of the high level of s character in the sp hybridized orbital, which bonds with the s orbital of the hydrogen atom to form a single bond. This very high level of s character in an sp‐hybridized carbon causes the region of overlap the σ bond to shift much closer to the carbon atom. This effect leads to a polarization the bond, causing the hydrogen atom to become slightly positive. This slight positive charge makes the acetylinic hydrogen atom a weak proton, which can be removed by a strong base.

In the case of alkanes and alkenes, the s character in the hybridized carbon bonds is much less than that of the acetylinic bond, resulting in fewer electronegative carbon atoms and a corresponding lesser shift of electron density toward those atoms in the overlap region of the σ bond. The location of the overlap region makes the corresponding hydrogen atoms less electron deficient and thus less acidic than the acetylinic hydrogen. In reality, the hydrogen atoms bonded to alkanes and alkenes can be removed as protons, but much stronger nonaqueous bases are necessary.

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Based on the three formulas shown, use one of them to solve for the purple yellow and red box and explain how you did it.
zysi [14]

P = 11.133 atm (purple)

T = -236.733 °C(yellow)

n = 0.174 mol(red)

<h3>Further explanation  </h3>

Some of the laws regarding gas, can apply to ideal gas (volume expansion does not occur when the gas is heated),:  

  • Boyle's law at constant T, P = 1 / V  
  • Charles's law, at constant P, V = T  
  • Avogadro's law, at constant P and T, V = n  

So that the three laws can be combined into a single gas equation, the ideal gas equation  

In general, the gas equation can be written  

\large {\boxed {\bold {PV = nRT}}}

where  

P = pressure, atm  

V = volume, liter  

n = number of moles  

R = gas constant = 0.08206 L.atm / mol K  

T = temperature, Kelvin  

To choose the formula used, we refer to the data provided

Because the data provided are temperature, pressure, volume and moles, than we use the formula PV = nRT

  • Purple box

T= 10 +273.15 = 373.15 K

V=5.5 L

n=2 mol

\tt P=\dfrac{nRT}{V}\\\\P=\dfrac{2\times 0.08205\times 373.15}{5.5}\\\\P=11.133~atm

  • Yellow box

V=8.3 L

P=1.8 atm

n=5 mol

\tt T=\dfrac{PV}{nR}\\\\T=\dfrac{1.8\times 8.3}{5\times 0.08205}\\\\T=36.42~K=-236.733^oC

  • Red box

T = 12 + 273.15 = 285.15 K

V=3.4 L

P=1.2 atm

\tt n=\dfrac{PV}{RT}\\\\n=\dfrac{1.2\times 3.4}{0.08205\times 285.15}\\\\n=0.174~mol

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Marat540 [252]

Answer:

Cannot be determined

Explanation:

Hi there,

Could you please add an attachment of the table? We cannot tell what the errors are if there is no table.

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2 years ago
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Answer:

me ig

Explanation:

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The compound trimethylamine, (CH3)3N, is a weak base when dissolved in water. Write the Kb expression for the weak base equilibr
Rina8888 [55]

<u>Answer:</u> The expression of K_b is written below.

<u>Explanation:</u>

We are given a chemical compound which is trimethylamine that acts as a weak base when dissolved in water.

It accepts a proton from the water to form trimethylammonium ion and hydroxide ion.

The chemical equation for the reaction of trimethylamine in water follows:

(CH_3)_3N+H_2O\rightleftharpoons (CH_3)_3NH^++OH^-

The expression of K_b for above equation follows:

K_b=\frac{[(CH_3)_3NH^+][OH^-]}{[(CH_3)_3N]}

Hence, the expression of K_b is written above.

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A neutral pH level is _____.<br> 5<br> 7<br> 8
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Neutral pH is level 7
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