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3 years ago

How much heat is lost when 0.440 mol of steam condenses at 100 °C?

Chemistry

1 answer:

dusya [7]3 years ago

8 0

Answer:

17,890 J

Explanation:

The amount of heat released by a gaseous substance when it condenses is given by the formula

$Q=n\lambda_v$

where

n is the number of moles of the substance

$\lambda_v$ is the latent heat of vaporization

The formula can be applied if the substance is at its vaporization temperature.

In this problem, we have:

n = 0.440 mol is the number of moles of steam

$\lambda_v=40,660 J/mol$ is the latent heat of vaporization of water

And the steam is already at 100C, so we can apply the formula:

$Q=(0.440)(40660)=17,890 J$

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A student is reading the volume from a standard 50-mL buret identical to what you used in the lab. The bottom of the meniscus is

Nutka1998 [239]

Answer:

20 mL

Explanation:

The student should record 20 mL as the correct volume.

The curved surface of a liquid that is usually observed in a buret is referred to as the meniscus. This meniscus is created as a result of the surface tension of the liquid against the walls of the buret. Hence, in order to avoid errors due to parallax, the bottom of the meniscus should be read and not the top.

Therefore, the correct volume that the student should record is 20 mL.

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3 years ago

For a reaction to be spontaneous under standard conditions at all temperatures, the signs of δh° and δs° must be __________ and

Shalnov [3]

For a reaction to be spontaneous under standard conditions at all temperatures, the signs of ΔH° and ΔS° must be negative and positive, respectively.
Gibbs free energy (G) determines if reaction will proceed spontaneously, if ΔG is negative, reaction is spontaneous.
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ΔG - changes in Gibbs free energy.
ΔH - changes in enthalpy.
ΔS - changes in entropy.
T is temperature in Kelvins.

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3 years ago

HI decomposes to H2 and I2 by the following equation: 2HI(g) → H2(g) + I2(g);Kc = 1.6 × 10−3 at 25∘C If 1.0 M HI is placed into

dsp73

Answer: The concentration of hydrogen gas at equilibrium is 0.037 M

Explanation:

We are given:

Initial concentration of HI = 1.0 M

The given chemical equation follows:

$2HI(g)\rightleftharpoons H_2(g)+I_2(g)$

Initial: 1.0

At eqllm: 1.0-2x x x

The expression of $K_c$ for above equation follows:

$K_c=\frac{[H_2][I_2]}{[HI]^2}$

We are given:

$Kc=1.6\times 10^{-3}$

Putting values in above expression, we get:

$1.6\times 10^{-3}=\frac{x\times x}{(1.0-2x)^2}\\\\x=-0.043,0.037$

Neglecting the negative value of 'x' because concentration cannot be negative

So, equilibrium concentration of hydrogen gas = x = 0.037 M

Hence, the concentration of hydrogen gas at equilibrium is 0.037 M

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2 years ago

The electron stable state configuration in atoms is best seen in the ______ configuration.

mamaluj [8]

The electron stable state configuration in atoms is best seen in the inert gas configuration.
Inert gas are the most stable since they have their valence electron shell saturated with electrons (the valence shell has the maximum number of electrons it can hold). They need neither donate nor accept electrons.

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3 years ago

What creates an ionic bond?

Anna71 [15]

Answer:c

Explanation: it’s c

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3 years ago