Question

How much heat is lost when 0.440 mol of steam condenses at 100 °C?

Answer 1

Answer:

17,890 J

Explanation:

The amount of heat released by a gaseous substance when it condenses is given by the formula

$Q=n\lambda_v$

where

n is the number of moles of the substance

$\lambda_v$ is the latent heat of vaporization

The formula can be applied if the substance is at its vaporization temperature.

In this problem, we have:

n = 0.440 mol is the number of moles of steam

$\lambda_v=40,660 J/mol$ is the latent heat of vaporization of water

And the steam is already at 100C, so we can apply the formula:

$Q=(0.440)(40660)=17,890 J$