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3 years ago

11

Chemical formula for aluminum hydroxide is Al(OH)3 which of the following is true aluminum

1 answer:

frozen [14]3 years ago

4 0

The answer to yo question is ( it has three OH groups).

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In a 10-gram sample of carbon and a 10-gram sample of sulfur, how many more moles of carbon are there than sulfur?

8_murik_8 [283]

Your answer will be the second option

5 0

2 years ago

Read 2 more answers

The bonds of the product store 27 KJ more energy than the bonds of the reactants how is energy conserved during this reaction

Blababa [14]

If the bonds of the product store 27 KJ more energy than the bonds of the reactants, It means the surroundings absorb 27 kj of energy from the reaction system Hence, Option (D) is the correct answer

<h3>What is the Exothermic reaction ?</h3>

An exothermic process releases heat, causing the temperature of the immediate surroundings to rise.

The bonds of the product store 27 KJ more energy than the bonds of the reactants, It means that energy has been absorbed by the surrounding as the product formed is more stable due to more stronger bond

This can be inferred from more stored energy with in the bonds and Thus, It is a exothermic reaction.Hence, Option (D) is the correct answer

Learn more about exothermic reaction here ;

brainly.com/question/9799465

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6 0

1 year ago

__is a term that refers to the amount of space that a substance or an object takes up

Anni [7]

Volume perhaps ?

Hope this helps !

3 0

2 years ago

In acidic solution, the sulfate ion can be used to react with a number of metal ions. One such reaction is SO42−(aq)+Sn2+(aq)→H2

allsm [11]

Answer:

The final balanced equation is :

$SO_4^{2-}(aq)+4H^+(aq)+Sn^{2+}(aq)\rightarrow H_2SO_3(aq)+H_2O(l)+Sn^{4+}(aq)$

Explanation:

$SO_4^{2-}(aq)+Sn^{2+}(aq)\rightarrow H_2SO_3(aq)+Sn^{4+}(aq)$

Balancing in acidic medium:

First we will determine the oxidation and reduction reaction from the givne reaction :

Oxidation:

$Sn^{2+}(aq)\rightarrow Sn^{4+}(aq)$

Balance the charge by adding 2 electrons on product side:

$Sn^{2+}(aq)\rightarrow Sn^{4+}(aq)+2e^-$ ....[1]

Reduction :

$SO_4^{2-}(aq)\rightarrow H_2SO_3(aq)$

Balance O by adding water on required side:

$SO_4^{2-}(aq)\rightarrow H_2SO_3(aq)+H_2O(l)$

Now, balance H by adding $H^+$ on the required side:

$SO_4^{2-}(aq)+4H^+(aq)\rightarrow H_2SO_3(aq)+H_2O(l)$

At last balance the charge by adding electrons on the side where positive charge is more:

$SO_4^{2-}(aq)+4H^+(aq)+2e^-\rightarrow H_2SO_3(aq)+H_2O(l)$ ..[2]

Adding [1] and [2]:

$SO_4^{2-}(aq)+4H^+(aq)+Sn^{2+}(aq)\rightarrow H_2SO_3(aq)+H_2O(l)+Sn^{4+}(aq)$

The final balanced equation is :

$SO_4^{2-}(aq)+4H^+(aq)+Sn^{2+}(aq)\rightarrow H_2SO_3(aq)+H_2O(l)+Sn^{4+}(aq)$

4 0

2 years ago

Can anyone fill in the answers?

Arte-miy333 [17]

Hi, P.S. The atomic number will always be the same as the number of protons...

6 0

2 years ago