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3 years ago

At what temperature would 0.500 moles of gas particles stored in a 100.0 mL container reach a pressure of 15.0 atm?

2 answers:

8 0

We use the ideal gas equation in order to calculate the temperature of the system. It is expressed as follows:

PV=nRT

where P is pressure, V is volume, n is the number of moles, R is the universal gas constant and T is the temperature.

15 atm (.1 L) = 0.5 mol (0.08206 L-atm / mol-K) T
T = 36.56 K

Hope this answers the question. Have a nice day.

sergeinik [125]3 years ago

4 0

Ideal gas law: p·V = n·R·T.

p = 15.0 atm; pressure of gas.

V = 100 mL ÷ 1000 mL/L.

V = 0.100 L; volume of gas.

n = 0.500 mol; amount of substance.

R = 0,08206 L·atm/mol·K; universal gas constant.

T = ?; temperature of gas.

T(gas) = p · V ÷ (R · n).

T(gas) = 15.0 atm · 0.1 L ÷ (0,08206 L·atm/mol·K · 0.5 mol).

T(gas) = 36,500 K; calculation is correct.

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2 years ago

A sample of methane (CH4) has a volume of 25 mL at a pressure of 0.80 atm. What is the volume of the gas at each of the followin

Xelga [282]

Answer:

a. 50ml b.10ml c. 6.097ml d. 190.1 ml

Explanation:

According to Boyle's law

Volume is inversely proportional to pressure at constant temerature

Mathematically

P1V1=P2V2

P1=Initial pressure=0.8atm

V1=Initial volume=25ml

making V2 the subject

at 0.4atm P2=0.4 atm,

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=6.097 ml

at 80.0 torr

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3 years ago

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11111nata11111 [884]

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3 years ago

For a tablet containing 500. mg of vitamin C, calculate how many ml of 0.095 M NaOH is required to reach the equivalence point.

Gala2k [10]

Answer:

mL of NaOH required =29.9mL

Explanation:

Let us calculate the moles of vitamin C in the tablet:

The molar mass of Vitamin C is 176.14 g/mole

$moles=\frac{mass}{molarmass}=\frac{500mg}{176.14}=\frac{0.5}{176.14}=0.0028$

Thus we need same number of moles of NaOH to reach the equivalence point.

For NaOH solution:

$moles=MolarityXvolume=0.095Xvolume$

$0.00283=0.095Xvolume$

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3 years ago

To what volume should 5.0 g of KCl be diluted in order to prepare a 0.15 M solution? L

Nesterboy [21]

Answer:0.45L

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Molecular mass of KCL=39.0983x1+35.453x1

Molecular mass of KCL=74.5513

No of moles=5 ➗ 74.5513

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Volume in liters=0.067 ➗ 0.15

Volume in liters=0.45L

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3 years ago