Answer:
A. The concentration of Na^+ in the solution is 6.75 M.
B. The concentration of PO4^3- in the solution is 2.25 M.
Explanation:
We'll begin by writing the balanced dissociation equation for Na3PO4.
This is illustrated below:
Na3PO4 will dissociate in solution as follow:
Na3PO4(aq) —> 3Na^+(aq) + PO4^3-(aq)
Thus, from the balanced equation above,
1 mole of Na3PO4 produce 3 moles of Na^+ and 1 mole of PO4^3-
A. Determination of the concentration of Na+ in 2.25 M Na3PO4 solution.
This can be obtained as follow:
From the balanced equation above,
1 mole of Na3PO4 produce 3 moles of Na^+.
Therefore, 2.25 M Na3PO4 solution will produce = (2.25 x 3) /1 = 6.75 M Na^+.
Therefore, the concentration of Na^+ in the solution is 6.75 M
B. Determination of the concentration of PO4^3- in 2.25 M Na3PO4 solution.
This can be obtained as follow:
From the balanced equation above,
1 mole of Na3PO4 produce 1 mole of PO4^3-
Therefore, 2.25 M Na3PO4 solution will also produce 2.25 M PO4^3-.
Therefore, the concentration of PO4^3- in the solution is 2.25 M.
= 150 molecules O₂