At what temperature would 0.500 moles of gas particles stored in a 100.0 mL container reach a pressure of 15.0 atm?

2 answers:

8 0

We use the ideal gas equation in order to calculate the temperature of the system. It is expressed as follows:

PV=nRT

where P is pressure, V is volume, n is the number of moles, R is the universal gas constant and T is the temperature.

15 atm (.1 L) = 0.5 mol (0.08206 L-atm / mol-K) T
T = 36.56 K

Hope this answers the question. Have a nice day.

sergeinik [125]3 years ago

4 0

Ideal gas law: p·V = n·R·T.

p = 15.0 atm; pressure of gas.

V = 100 mL ÷ 1000 mL/L.

V = 0.100 L; volume of gas.

n = 0.500 mol; amount of substance.

R = 0,08206 L·atm/mol·K; universal gas constant.

T = ?; temperature of gas.

T(gas) = p · V ÷ (R · n).

T(gas) = 15.0 atm · 0.1 L ÷ (0,08206 L·atm/mol·K · 0.5 mol).

T(gas) = 36,500 K; calculation is correct.

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