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Diano4ka-milaya [45]
2 years ago
14

At what temperature would 0.500 moles of gas particles stored in a 100.0 mL container reach a pressure of 15.0 atm?

Chemistry
2 answers:
pychu [463]2 years ago
8 0
We use the ideal gas equation in order to calculate the temperature of the system. It is expressed as follows:

PV=nRT

where P is pressure, V is volume, n is the number of moles, R is the universal gas constant and T is the temperature.

15 atm (.1 L) = 0.5 mol (0.08206 L-atm / mol-K) T
T = 36.56 K

Hope this answers the question. Have a nice day.
sergeinik [125]2 years ago
4 0

Ideal gas law: p·V = n·R·T.

p = 15.0 atm; pressure of gas.

V = 100 mL ÷ 1000 mL/L.

V = 0.100 L; volume of gas.

n = 0.500 mol; amount of substance.

R = 0,08206 L·atm/mol·K; universal gas constant.

T = ?; temperature of gas.

T(gas) = p · V ÷ (R · n).

T(gas) = 15.0 atm · 0.1 L ÷ (0,08206 L·atm/mol·K · 0.5 mol).

T(gas) =  36,500 K; calculation is correct.


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The answer:
all that we search for is the number of mole of HCl and the number of mole of C2H6O

M(HCl) = 5.5g/ mole of HCl , so mole of HCl = 5.5/M(HCl), where M(HCl) is the molar mass.
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moles of HCl = 5.5/37.5=0.14 

M(C2H6O) = 200g / moles of C2H6O, so moles of C2H6O=200g / M(C2H6O)

M(C2H6O)= 2x12+ 6 + 16=46,

moles of C2H6O=200g / 46 =<span>4.35 </span><span> moles 
</span>
the sum of the moles is    0.14 + <span>4.35 </span> = 4.501 moles

finally,  <span>The mole fraction of hcl in a solution prepared by dissolving 5.5 g of hcl in 200 g of c2h6o is 0.031
</span>
because it can be found by  0.14 / 4.501= 0.031

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