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3 years ago

6

as electrons are passed through the system of electron carriers associated with photosystem ii, they lose energy. what happens t

o this energy?

1 answer:

katrin2010 [14]3 years ago

7 0

They break up and become only positive energy

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What is the viscosity and flammability of refinery gas?

Liono4ka [1.6K]

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3 years ago

A method used by the U.S. Environmental Protection Agency (EPA) for determining the concentration of ozone in air is to pass the

baherus [9]

Answer: 1. $9.08\times 10^{-6}$ moles

2. 90 mg

Explanation:

$O_3(g)+2NaI(aq)+H_2O(l) \rightarrow O_2(g)+I_2(s)+2NaOH(aq)$

According to stoichiometry:

1 mole of ozone is removed by 2 moles of sodium iodide.

Thus $4.54 \times 10^{-6}$ moles of ozone is removed by = $\frac{2}{1}\times 4.54 \times 10^{-6}=9.08\times 10^{-6}$ moles of sodium iodide.

Thus $9.08\times 10^{-6}$ moles of sodium iodide are needed to remove $4.54\times 10^{-6}$ moles of $O_3$

2. $\text{Number of moles of ozone}=\frac{0.01331g}{48g/mol}=0.0003moles$

According to stoichiometry:

1 mole of ozone is removed by 2 moles of sodium iodide.

Thus 0.0003 moles of ozone is removed by = $\frac{2}{1}\times 0.0003=0.0006$ moles of sodium iodide.

Mass of sodium iodide= $moles\times {\text {molar mass}}=0.0006\times 150g/mol=0.09g=90mg$ (1g=1000mg)

Thus 90 mg of sodium iodide are needed to remove 13.31 mg of $O_3$ .

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3 years ago

4HF(g)+SiO2(s)→SiF4(g)+2H2O(l)

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<span>Gallium-72 that is what i got when i did the math for it</span>

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3 years ago

F(x) = 2|x+2| - 8 I need help

Korolek [52]

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Explanation: not sure if this is right im just guessing

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The correct option is D.
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3 years ago