What is the viscosity and flammability of refinery gas?
1 answer:
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Answer:
C. 548mL
Explanation:
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Answer= 2 mol/dm^3
Explanation:-
Firstly, we convert the volume, which is in cm^3 to dm^3. To do that divide number in cm^3 by 1000:
100/1000= 0.1 dm^3
Formula for concentration is:
Concentration= No. of moles/ Volume
So,
Concentration= 0.2/0.1
Answer= 2 mol/dm^3
Explanation:-
Firstly, we convert the volume, which is in cm^3 to dm^3. To do that divide number in cm^3 by 1000:
100/1000= 0.1 dm^3
Formula for concentration is:
Concentration= No. of moles/ Volume
So,
Concentration= 0.2/0.1
Answer= 2 mol/dm^3