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3 years ago

Since the action and reaction are exactly equal and oppositely directed , how can there be a net force on an object ?

Chemistry

1 answer:

erma4kov [3.2K]3 years ago

6 0

Answer: Net force is the summation of all the forces involved or acting on an object.

Explanation: For action and reaction situation it states that the Fa = -Fb. Both forces with equal magnitudes but opposite direction will cancel out each other having a zero net force.

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At 298 K, the osmotic pressure of a glucose solution (C6H12O6 (aq)) is 12.1 atm. Calculate the freezing point of the solution. T

Anarel [89]

Answer: The freezing point of solution is -0.974°C

Explanation:

To calculate the concentration of solute, we use the equation for osmotic pressure, which is:

$\pi=iMRT$

where,

$\pi$ = osmotic pressure of the solution = 12.1 atm

i = Van't hoff factor = 1 (for non-electrolytes)

M = molarity of solute = ?

R = Gas constant = $0.0821\text{ L atm }mol^{-1}K^{-1}$

T = temperature of the solution = 298 K

Putting values in above equation, we get:

$12.1atm=1\times M\times 0.0821\text{ L.atm }mol^{-1}K^{-1}\times 298K\\\\M=\frac{12.1}{1\times 0.0821\times 298}=0.495M$

This means that 0.495 moles of glucose is present in 1 L or 1000 mL of solution

To calculate the mass of solution, we use the equation:

$\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}$

Density of solution = 1.034 g/mL

Volume of solution = 1000 mL

Putting values in above equation, we get:

$1.034g/mL=\frac{\text{Mass of solution}}{1000mL}\\\\\text{Mass of solution}=(1.034g/mL\times 1000mL)=1034g$

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Moles of glucose = 0.495 moles

Molar mass of glucose = 180.16 g/mol

Putting values in above equation, we get:

$0.495mol=\frac{\text{Mass of glucose}}{180.16g/mol}\\\\\text{Mass of glucose}=(0.495mol\times 180.16g/mol)=89.18g$

Depression in freezing point is defined as the difference in the freezing point of pure solution and freezing point of solution.

The equation used to calculate depression in freezing point follows:

$\Delta T_f=\text{Freezing point of pure solution}-\text{Freezing point of solution}$

To calculate the depression in freezing point, we use the equation:

$\Delta T_f=iK_fm$

Or,

$\text{Freezing point of pure solution}-\text{Freezing point of solution}=i\times K_f\times \frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ (in grams)}}$

where,

Freezing point of pure solution = 0°C

i = Vant hoff factor = 1 (For non-electrolytes)

$K_f$ = molal freezing point elevation constant = 1.86°C/m

$m_{solute}$ = Given mass of solute (glucose) = 89.18 g

$M_{solute}$ = Molar mass of solute (glucose) = 180.16 g/mol

$W_{solvent}$ = Mass of solvent (water) = [1034 - 89.18] g = 944.82 g

Putting values in above equation, we get:

$0-\text{Freezing point of solution}=1\times 1.86^oC/m\times \frac{89.18\times 1000}{180.16g/mol\times 944.82}\\\\\text{Freezing point of solution}=-0.974^oC$

Hence, the freezing point of solution is -0.974°C

8 0

3 years ago

If the caffeine concentration in a particular brand of soda is 3.55 mg/oz, drinking how many cans of soda would be lethal? Assum

monitta

Answer:

The answer to your question is: 234.7 cans

Explanation:

data

caffeine concentration = 3.55 mg/oz

10.0 g of caffeine is lethal

there are 12 oz of caffeine in a can

Then

3.55 mg ----------------- 1 oz

x mg -----------------12 oz (in a can)

x = 42.6 mg of caffeine in a can

Convert it to grams 42,6 mg = 0.0426 g of caffeine in a can

Finally

0.0426 g of caffeine ------------------ 1 can

10 g of caffeine ----------------- x

x = 10 x 1/0.0436 = 234.7 cans

6 0

3 years ago

How many sodium atoms will create an ionic bond with sulfur?

Galina-37 [17]

Hi,

Two sodium atoms are needed to create an ionic bond with sulfur.

5 0

3 years ago

A chemical reaction produces formaldehyde, with a chemical formula of CH2O. Carbon is in group 4A, Oxygen is in group 6A, and Hy

steposvetlana [31]

Answer:

Explanation:

carbon in group 4A needs 4 more electrons to be stable

hydrogen in group 1A has one electron needs 1 more t o be stale

oxygen in group 6A has 6 and needs 2 more to be stable

They all obtain this by sharing electrons 8 around C &O, 2 around H

H : C: H

:O:

5 0

2 years ago

Describe a chemical formula give an example

Vlad1618 [11]

A chemical formula identifies each constituent element by its chemical symbol and indicates the proportionate number of atoms of each element.

For example, the empirical formula of ethanol may be written C2H6O because the molecules of ethanol all contain two carbon atoms, six hydrogen atoms, and one oxygen atom.

3 0

3 years ago