As we know that rate law expression is

(a)

(b)

(c)

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The answer is 200 J
The kinetic energy (KE) is:
KE = 1/2 m * v²
m - mass of the object
v - velocity of the object
We have:
m = 4 kg
v = 10 m/s
KE = 1/2 * 4 kg * 10² m/s
KE = 200 J
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The number of moles present in 29.5 grams of argon is 0.74 mole.
The atomic mass of argon is given as;
Ar = 39.95 g/mole
The number of moles present in 29.5 grams of argon is calculated as follows;
39.95 g ------------------------------- 1 mole
29.5 g ------------------------------ ?

Thus, the number of moles present in 29.5 grams of argon is 0.74 mole.
<em>"Your question seems to be missing the correct symbol for the element" </em>
Argon = Ar
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Answer: I would say its either exit door or the last one.
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