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Sauron [17]
3 years ago
11

g How many turns through the citric acid cycle are required to fully oxidize all of the acetly-coA that result from 1 molecule o

f glucose?
Chemistry
1 answer:
faust18 [17]3 years ago
7 0

Answer:

The two molecules of acetyl-CoA that are produced from a molecule of glucose goes through two turn in the citric acid cycle, one for each molecule of acetyl-CoA.

Explanation:

Glycolysis the process by which a molecule of glucose is broken down in a series of steps to yield two molecules of pyruvate. The overall equation for  the reactions of glycolsis is given below:

Glucose + 2NAD+ ----> 2 Pyruvate + 2NADH + 2H⁺

Each of the two pyruvate molecules produced from glucose breakdown is further oxidized to two molecules of acetyl-CoA and CO₂ each.

2 Pyruvate ----> 2 AcetylCoA + 2CO₂

Each of the acetyl-CoA molecule then enters the citric acid cycle for its oxidation. In each turn of the cycle, one acetyl group enters as acetyl-CoA and two molecules of CO₂ leave.

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vitfil [10]

Answer:I believe your answer would be option B) dilute. Hope this helps.

Explanation:

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Answer:

True.

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3 years ago
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sukhopar [10]

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. Explain why, in the sample calculations, 0.1 g of the unknown produced a GREATER freezing point depression than~e same mass of
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Ca(NO3)2 >> Ca2+ + 2 NO3- => 3 ions)

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