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Sauron [17]
3 years ago
11

g How many turns through the citric acid cycle are required to fully oxidize all of the acetly-coA that result from 1 molecule o

f glucose?
Chemistry
1 answer:
faust18 [17]3 years ago
7 0

Answer:

The two molecules of acetyl-CoA that are produced from a molecule of glucose goes through two turn in the citric acid cycle, one for each molecule of acetyl-CoA.

Explanation:

Glycolysis the process by which a molecule of glucose is broken down in a series of steps to yield two molecules of pyruvate. The overall equation for  the reactions of glycolsis is given below:

Glucose + 2NAD+ ----> 2 Pyruvate + 2NADH + 2H⁺

Each of the two pyruvate molecules produced from glucose breakdown is further oxidized to two molecules of acetyl-CoA and CO₂ each.

2 Pyruvate ----> 2 AcetylCoA + 2CO₂

Each of the acetyl-CoA molecule then enters the citric acid cycle for its oxidation. In each turn of the cycle, one acetyl group enters as acetyl-CoA and two molecules of CO₂ leave.

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Yesterday we combined Hydrochloric Acid HCl with Sodium Hydroxide NaOH in a violent reaction that resulted in water H2O and comm
IceJOKER [234]
Reaction:
<span>HCl + NaOH ---> NaCl + H2O

</span><span>1 mole of HCl = 36,5 g
</span><span>1 mole of NaOH = 40g

</span><span>so, according to the reaction:
</span><span>1 mol HCl = 1 mol NaOH
</span>so, we need > 36,5 g HCl (<u>hydrochloric acid</u><span>)
</span><u>
answer: 36,5 g HCl (hydrochloric acid)
</u><span> ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~
</span><span>next question.
</span><span>
1 mole of NaCl = 58,5 g
</span><span>1 mole of H2O = 18g
</span>
so, according to the reaction:
1 mole of HCl (36,5 g) <span>----------------- - 1 mole of NaCl (58,5 g)
</span><span>(the same for NaOH)
i
</span>1 mole of HCl<span> (36,5 g) ------------------ 1 mole of H2O (18 g)
</span>(the same for NaOH)

<span>so, this reaction is stechiometric
</span><u>
answer: 58,5 g NaCl i 18g H2O</u>
7 0
3 years ago
Read 2 more answers
Which is less likely to be a relatable source of information the webpage of a university or the webpage a scientist who is tryin
faltersainse [42]

Answer:

The web page of a university

Explanation:

A scientist can be more biased within coming to information about pretty much anything. I have had multiple science teachers who seem more biased on to something else and pretend that they're right just cause they know what they are doing.

Then the university would be a great choice because its controlled by a higher state, then also the consistency of being updated.

7 0
3 years ago
1. फल
Allisa [31]

Answer:

बालकेभ्य।

2 गुरुभि :

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5 0
3 years ago
A solution is formed by mixing 0.400 mol NaOH
leonid [27]

Answer:

The correct answer is m= mol solute kg soivent

Explanation:

Molality is a measure of concentration, which indicates the moles of solute (in this case sodium hydroxide) in 1kg of solvent .

In this case:

0,800 kg water-----0,400 mol NaOH

1 ,000 kg water ---x=(1 ,000 kg water x 0,400 mol NaOH)/0,800 kg water

x=0,5 mol NaOH---> <em>The solution is 0,5 molal (0,5 m)</em>

6 0
3 years ago
What bond vibrations and stretching frequencies should you observe in the IR spectrum of caffeine?
Margarita [4]
  • The bond vibrations that can be observed in the IR spectrum of caffeine :

i) asymmetric, ii) symmetric, iii) wagging, iv) twisting, v) scissoring, vi) rocking

  • while the observable stretching frequencies are ; 1700, 1300, 2900, 1500 and 3000.

Caffeine is a polyatomic molecule ( contains more than two atoms bonded via covalent bonds )  therefore its atoms can vibrate in three dimensions ( x, y, z ).therefore the bond vibrations that can be observed in the IR spectrum of caffeine are :  asymmetric, symmetric, wagging, twisting, scissoring, and rocking.

The observable stretching frequencies that are in the IR spectrum of caffeine ; C = O is 1700 ,  C - H is 1300,  C -H is 2900,  C -N is 1500, and N -H = 3000.

Hence we can conclude The bond vibrations that can be observed in the IR spectrum of caffeine : i) asymmetric, ii) symmetric, iii) wagging, iv) twisting, v) scissoring, vi) rocking and the observable stretching frequencies are ; 1700, 1300, 2900, 1500 and 3000.

Learn more : brainly.com/question/13184210

3 0
2 years ago
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