Answer:
Molarity of a solution that contains 3.11 mol of NaNO3 is 1,24 M
Explanation:
We understand molarity as the number of moles of solute that are contained in 1 L of solution, then if in a solution of 2.50 L we have 3.11 moles, it remains to calculate how many moles do we have in 1 liter.
2,50 L .......... 3,11 moles
1 L .................. x
X = ( 1 L x 3,11 moles) / 2,50 L = 1,24
Answer:
65 ml
Explanation:
The aluminum will not float , so it will displace a volume of fluid equal to its volume.
13.5 gm / 2.7 gm/ml = 5 ml
the new graduated cylinder measurement will be 60 + 5 = 65 ml
The answer is b, corporation
Oh my i really hope no one from my school sees my comments
Answer:
Mass = 58.96 g
Explanation:
Given data:
Mass of CH₄ = 21.5 g
Mass of O₂ = 387.5 g
Mass of CO₂ formed = ?
Solution:
Chemical equation:
CH₄ + 2O₂ → CO₂ + 2H₂O
Number of moles of CH₄:
Number of moles = mass / molar mass
Number of moles = 21.5 g/ 16 g/mol
Number of moles = 1.34 mol
Number of moles of O₂ :
Number of moles = mass / molar mass
Number of moles = 387.5 g/ 32 g/mol
Number of moles = 12.1 mol
now we will compare the moles of CO₂ with O₂ and CH₄.
O₂ : CO₂
2 : 1
12.1 : 1/2×12.1 = 6.05 mol
CH₄ : CO₂
1 : 1
1.34 : 1.34
Number of moles of CO₂ produced by CH₄ are less thus it will limiting reactant.
Mass of CO₂:
Mass = number of moles × molar mass
Mass = 1.34 mol × 44 g/mol
Mass = 58.96 g
