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Mandarinka [93]
3 years ago
8

This molecule can be synthesized from an alkyne anion and an alkyl bromide. However, there are two ways in which this molecule c

an be formed. One way uses a higher molecular weight alkyne anion (Part 1) and the other uses a lower molecular weight anion (Part 2). Draw the two versions in the boxes below. Omit spectator ions.

Chemistry
1 answer:
kozerog [31]3 years ago
4 0

Answer:

See figures

Explanation:

In this case, we will have different options around the<u> triple bond</u>. On part 1 we have to use the <u>bigger anion</u>, so we have to use the anion in which the <u>benzene ring is included </u>therefore the <u>ethyl</u> would be the <u>halide</u> (see figure 1).

On part 2 we have to use the <u>smaller anion</u>, so the <u>ethyl group</u> would be the anion and the other part of the molecule would be the <u>alkyl halide</u> (see figure 2).

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What is the most soluble salt of the following set? What is the most soluble salt of the following set?
DiKsa [7]

Answer:

(c) AgCN\ (K_{sp} =6.0\times 10^{-17})

Explanation:

The solubility product of a solid is the amount of solid dissociates into its respective ions in the solution. Thus more the value of the Ksp, the more is the salt soluble in the solvent.

So,  Given that:-

Sn(OH)_2\ (K_{sp} =1.6\times 10^{-19})

Al(OH)_3\ (K_{sp} =1.9\times 10^{-33})

AgCN\ (K_{sp} =6.0\times 10^{-17})

Fe(OH)_3\ (K_{sp} =2.6\times 10^{-39})

The salt having highest value of Ksp is AgCN. So, it is most soluble.

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When you put aspirated spinach leaf disks in a beaker of sodium bicarbonate and place them in different colors of light, some di
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The release of O₂( oxygen) from the process of photosynthesis is what made them to be able to float.

<h3>What is Photosynthesis?</h3>

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The reactants mentioned above undergo series of reactions which leads to the production of glucose and oxygen is given off as a result which is the element responsible for the floating of the aspirated spinach leaf disks in this scenario.

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3 0
1 year ago
How many moles are in 2.98x10^23 particles?
Novosadov [1.4K]

Answer:

\boxed {\boxed {\sf 0.495 \ mol}}

Explanation:

We are given a number of particles and asked to convert to moles.

<h3>1. Convert Particles to Moles </h3>

1 mole of any substance contains the same number of particles (atoms, molecules, formula units) : 6.022 *10²³ or Avogadro's Number. For this question, the particles are not specified.

So, we know that 1 mole of this substance contains 6.022 *10²³ particles. Let's set up a ratio.

\frac { 1 \ mol }{6.022*10^{23 } \ particles}}

We are converting 2.98*10²³ particles to moles, so we multiply the ratio by that value.

2.98*10^{23} \ particles *\frac { 1 \ mol }{6.022*10^{23 } \ particles}}

The units of particles cancel.

2.98*10^{23}  *\frac { 1 \ mol }{6.022*10^{23 } }}

\frac { 2.98*10^{23}}{6.022*10^{23 } }}  \ mol

0.4948522086 \ mol

<h3>2. Round</h3>

The original measurement of particles (2.98*10²³) has 3 significant figures, so our answer must have the same.

For the number we found, 3 sig figs is the thousandth place.

The 8 in the ten-thousandth place (0.4948522086) tells us to round the 4 up to a 5 in the thousandth place.

0.495 \ mol

2.98*10²³ particles are equal to approximately <u>0.495 moles.</u>

3 0
3 years ago
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