What is the mass of carbon in 290 g of CO2?
1 answer:
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CO₂ + H₂O -------> H₂CO₃
moles of CO₂ =
=
= 11.997 mol
mole ratio of CO₂ : H₂O = 1 : 1
∴ moles of H₂O = (`11.997 mol ) * 1
= 11.997 mol
≈ 12 mol
moles of CO₂ =
=
= 11.997 mol
mole ratio of CO₂ : H₂O = 1 : 1
∴ moles of H₂O = (`11.997 mol ) * 1
= 11.997 mol
≈ 12 mol
Answer:
m = 0.659 ounce
Explanation:
It is given that,
The thickness of a Teflon coating is, d = 1 mm
Area of the coating, A = 36 inch²
The density of Teflon, d = 0.805 g/mL
We need to find ounces of Teflon are needed.
Firstly, find the volume of the Teflon needed,
1 inch² = 6.4516 cm²
36 inch² = 232.258 cm²
Density,
V is volume of the Teflon needed, V = Ad
So,
Also, 1 gram = 0.035274 ounce
18.69 gram = 0.659 ounce
So, 0.659 ounces of Teflon are needed.