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elena-s [515]
4 years ago
14

How often will high tides occur?

Physics
2 answers:
sergiy2304 [10]4 years ago
5 0
Because the Earth rotates through two tidal<span> “bulges” every lunar day, coastal areas experience<em> two </em></span><em>high</em><span><em> and two low </em></span><em>tides</em><span><em> every 24 hours and 50 minutes</em>.

 </span>High tides occur<span> 12 hours and 25 minutes apart. It takes six hours and 12.5 minutes for the water at the shore to go from </span>high<span> to low, or from low to </span>high<span>.

I hope this helped!! Have an amazing day :))</span>
PSYCHO15rus [73]4 years ago
4 0
<h3>Answer:</h3><h2>(A) About twice a day. </h2><h3>Explanation:</h3>

Waterfront neighbourhoods encounter two low tides and two high tides each lunar day, or 24 hours and 50 minutes. The two tidal bumps are created by inertia and gravity which revolve around the Earth as the moons state shifts. These bumps indicate high tides while the smooth sides represent low tides.

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A liquid of density 1270 kg/m3 flows steadily through a pipe of varying diameter and height. At Location 1 along the pipe, the f
FinnZ [79.3K]

Answer:

{P_2}-P_1=49.99\ KPa

Explanation:

v_1=9.43\ m/s

d_1=11.7\ cm/s

d_2=17.5\ cm/s

From continuity equation

A_1v_1=A_2v_2

v_1d_1^2=v_2d_2^2

v_2=\dfrac{9.43\times 11.7^2}{17.5^2}

v_2=4.21\ m/s

\dfrac{P_1}{\rho g}+\dfrac{v_1^2}{2g}+y_1=\dfrac{P_2}{\rho g}+\dfrac{v_2^2}{2g}+y_2

{P_1}+\rho\dfrac{v_1^2}{2}+\rho y_1g={P_2}+\rho\dfrac{v_2^2}{2}+\rho y_2g

\rho\dfrac{v_1^2}{2}+\rho y_1g -\rho\dfrac{v_2^2}{2}-\rho y_2g={P_2}-P_1

1270\times \dfrac{9.43^2}{2}+1270\times 0\times 10 -1270\times\dfrac{4.21^2}{2}-1270\times 0.175\times 10={P_2}-P_1

{P_2}-P_1=49.99\ KPa

4 0
3 years ago
Slowing down is a type of acceleration true or false
Kryger [21]

Answer:

True.

Explanation:

It is called negative acceleration or deceleration. It is the opposite of acceleration.

3 0
3 years ago
A force of 62 N acts on a 35 kg object for 10.0s. What is the objects change in momentum?
Makovka662 [10]

Answer:

Δp = 620 N.s

Explanation:

  • Newton's second law, was originally conceived  as follows:

       F = \frac{\Delta p}{\Delta t}  (1)

  • In this way, a net force applied on an object, is equal to the rate of change of the momentum of the object regarding time.

       for m= constant, it reduces to F= m*a.

  • Replacing in (1) F= 62 N, and Δt = 10.0 s, we can solve for Δp (object's change in momentum) , as follows:

       \Delta p = F* \Delta t = 62 N* 10.0 s = 620 N*s  (2)

7 0
3 years ago
A secant and a tangent meet at a 90° angle outside the circle. What must be the difference between the measures of the interc
kozerog [31]

The difference between the measures of the intercepted arcs of the given circle is 45°.

A circle is defined as the set of points in a plane equidistant to each, such that it forms a closed two-dimensional figure, which is known as a circle.

  • A line intersecting a circle at a minimum of two distinct points is known as a secant and the line touching the circle at only one point, is known as the tangent of a circle.
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We are given that the angle subtended by secant and tangent, outside the circle is,

\theta =90^{\circ}

And angle measured inside the circle is,

\phi = \theta /2\\\\\phi = 90/2\\\\\phi = 45{^\circ}

So, the difference between the measures of the intercepted arcs is,

\theta' = \theta - \phi\\\\\theta' = 90-45\\\\\theta' =45^{\circ}

Thus, we can conclude that the difference between the measures of the intercepted arcs of the given circle is 45°.

learn more about the tangent here:

brainly.com/question/14022348

4 0
3 years ago
A closed system’s internal energy changes by 178 J as a result of being heated with 658 J of energy. The energy used to do work
nika2105 [10]

Answer:

480J

Explanation:

Using the formula:

Delta U = Q - W

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Delta U: Changes in internal Energy (J)

W:Work (J)

We can plug in the give numbers, Q and W.

Delta U = 658J - 178J = 480J

6 0
3 years ago
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