Question

A force of 62 N acts on a 35 kg object for 10.0s. What is the objects change in momentum?

Answer 1

Answer:

Δp = 620 N.s

Explanation:

• Newton's second law, was originally conceived  as follows:

       $F = \frac{\Delta p}{\Delta t} (1)$

• In this way, a net force applied on an object, is equal to the rate of change of the momentum of the object regarding time.

       for m= constant, it reduces to F= m*a.

• Replacing in (1) F= 62 N, and Δt = 10.0 s, we can solve for Δp (object's change in momentum) , as follows:

       $\Delta p = F* \Delta t = 62 N* 10.0 s = 620 N*s (2)$