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3 years ago

A force of 62 N acts on a 35 kg object for 10.0s. What is the objects change in momentum?

Physics

1 answer:

Makovka662 [10]3 years ago

7 0

Answer:

Δp = 620 N.s

Explanation:

Newton's second law, was originally conceived as follows:

$F = \frac{\Delta p}{\Delta t} (1)$

In this way, a net force applied on an object, is equal to the rate of change of the momentum of the object regarding time.

for m= constant, it reduces to F= m*a.

Replacing in (1) F= 62 N, and Δt = 10.0 s, we can solve for Δp (object's change in momentum) , as follows:

$\Delta p = F* \Delta t = 62 N* 10.0 s = 620 N*s (2)$

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