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yanalaym [24]
2 years ago
10

5. An infinite wire is 3.00 cm away from and parallel to a 10 cm long wire, and each has a current of 2.50 A in the same directi

on (for example the top wire of the rectangle in Fig. 4). (a) What is the magnetic field from the infinite wire at the position of the other wire
Physics
1 answer:
Step2247 [10]2 years ago
3 0

Answer:

B=1.04*10^{-4}T

Explanation:

An infinite wire produces a magnetic field that can be computed with the formula:

B=\frac{\mu_0 I}{2\pi r}

where m0 is the magnetic permeability of vacuum (4pi*10^{-7}Tm/A), I is the current of the wire (2.50A) and r is the perpendicular distance to the wire in which B is calculated (3cm=3*10^{-2}m). By replacing we obtain:

B=\frac{(4\pi*10^{-7}Tm/A)(2.50A)}{3*10^{-2}m}=1.04*10^{-4}T

hope this helps!!

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A circular loop of wire with a radius of 15.0 cm and oriented in the horizontal xy-plane is located in a region of uniform magne
bekas [8.4K]

Answer:

Explanation:

Given that,

Radius r = 15cm = 0.15m

Area of the circular loop can be determined using the formula for area of a circle

A = π r²

A = π × 0.15²

A = 0.0708 m²

Magnetic field B = 1.2T in positive z direction

B = 1.2 •k T.

If loop is remove from the field in the time interval

∆t = 2.3ms = 2.3×10^-3s

We want to find the average EMF and it is given as

ε = —∆Φ/∆t

The final flux is zero

Φf = 0

Where magnetic flux is given as

Φi = BA Cosθ

Where θ=0 since the area and the magnetic field point in the same direction.

Φi = BA Cos0

Φi = BA

Φi = 1.2 × 0.0708

Φi = 0.0848 Vs

Then, ε = —∆Φ/∆t

ε = —(Φf — Φi) / ∆t

ε = —(0-0.0848) / (2.3×10^-3)

ε = 0.0848 / (2.3×10^-3)

ε = 36.88 V

The EMF is 36.88 Volts

6 0
3 years ago
A stone is thrown upward at an angle. what happens to the horizontal component of its velocity as it rises? as it falls?
Ne4ueva [31]
<span>Rising or falling, it does not change.</span>
5 0
3 years ago
The normal force acting on an object and the force of static friction do zero work on the object. However the reason that the wo
spin [16.1K]

Answer:

<em>The normal force is perpendicular to the displacement</em>

<em>The static friction force produces no displacement</em>

Explanation:

Work Done By Special Forces

The work is a physical magnitude that measures the dot product of the force applied to an object by the displacement it produces in it.

W=\vec F\ \vec r

It can be written in its scalar version as

W=F.d.cos\theta

Being F and d the magnitudes of the force and displacement, and \theta the angle between them

If the angle is zero, the work is at maximum, it the angle is 90°, the work is zero. If the angle is between 90° and 180°, the work is negative.

The normal force acts in the vertical direction when the object is being pushed horizontally. It means the angle between the force and the displacement is 90°, thus the work is

W=N.d.cos90^o=0

The work is zero because the force and the displacement are perpendicular

The static friction force exists only when the object is being applied a force of a magnitude not large enough to produce movement, i.e. the object is at rest. If the object is moved, the friction force is still present, but it's called dynamic friction force, usually smaller than the static.

Since in this case, there is no displacement, d=0, and the work is

W=F_r(0)cos180^o=0

3 0
3 years ago
Number of conducting plates of a multiplate capacitor is 5. The no. Of capacitors is
Ivahew [28]

Answer:

4 capacitors

Explanation:

Given

n = 5 --- conducting plates

Required

The number of capacitor (c)

This is calculated as:

c = n - 1

So, we have:

c = 5 - 1

c = 4

8 0
2 years ago
For which question could a testable hypothesis be developed?
Mandarinka [93]
I believe it’s B; Theories may be proven to be true and become laws.
A would make sense if we were talking about hypotheses however, we’re not.
8 0
3 years ago
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