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4 years ago

How are Earth, the Moon and Sun alligned during a neap tide?

1 answer:

6 0

Neap tides occur at or immediately after the First Quarter
and Third Quarter moon phases. At those times, the moon
is 'to the side' of the Earth. I mean, the sun, Earth, and Moon
make a right angle, with Earth at the vertex.

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1. What is work done in holding a 15kg suitcase while waiting for a bus for 15 minutes?

Anettt [7]

The man is holding the suitcase at the same height above the surface of earth. So the gravitation potential energy remains the same.

<span>work done is force * displacement = weight * 0 = 0</span>

7 0

3 years ago

n isolated charged soap bubble of radius R0=7.45 cmR0=7.45 cm is at a potential of V0=307.0 volts.V0=307.0 volts. If the bubble

Gnesinka [82]

Complete Question

An isolated charged soap bubble of radius R0 = 7.45 cm is at a potential of V0=307.0 volts. V0=307.0 volts. If the bubble shrinks to a radius that is 19.0%19.0% of the initial radius, by how much does its electrostatic potential energy ????U change? Assume that the charge on the bubble is spread evenly over the surface, and that the total charge on the bubble r

Answer:

The difference is $U_f -U_i = 16 *10^{-7} J$

Explanation:

From the question we are told that

The radius of the soap bubble is $R_o = 7.45 \ cm = \frac{7.45}{100} = 0.0745 \ m$

The potential of the soap bubble is $V_1 =307.0 V$

The new radius of the soap bubble is $R_1 = 0.19 * 7.45=1.4155\ cm = 0.014155 \ m$

The initial electric potential is mathematically represented as

$U_i = \frac{V_1^2 R_o }{2k }$

The final electric potential is mathematically represented as

$U_f = \frac{V_2^2 R_1 }{2k }$

The initial potential is mathematically represented as

$V_1 = \frac{kQ}{R_o}$

The final potential is mathematically represented as

$V_2 = \frac{kQ}{R_1}$

Now

$\frac{V_2}{V_1} = \frac{R_o}{R_1}$

substituting values

$\frac{V_2}{V_1} = \frac{7.45}{1.4155} = \frac{1}{0.19}$

=> $V_2 = \frac{V_1}{0.19}$

$U_f = \frac{V_1^2 R_2 }{2k * 0.19^2}$

Therefore

$U_f -U_i = \frac{V_1^2 R_2 }{2k * 0.19^2} - \frac{V_1^2 R_o }{2k }$

$U_f -U_i = \frac{V_1^2}{2k} [\frac{ R_1 }{ * 0.19^2} - R_o]$

where k is the coulomb's constant with value $9*10^{9} \ kg\cdot m^3\cdot s^{-4}\cdot A^2.$

substituting values

$U_f -U_i = \frac{307^2}{9 * 10^{9}} [\frac{ 0.014155 }{ 0.19^2} - 0.0745]$

$U_f -U_i = 16 *10^{-7} J$

8 0

3 years ago

5. The most dangerous place to use electrical equipment is?

podryga [215]

C) because you could get hurt if certain items fall in it and you are in water

7 0

3 years ago

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Why do nuclear power plants use fission rather than fusion to generate

kicyunya [14]

B. Fusion requires very high pressure and temperature.

Explanation:

Nuclear fusion is the combination of atomic nuclei into larger ones with the release of a large amount of energy.

Nuclear fission is the decay process in which a heavy nuclide is bombarded with with neutrons.

Both processes release a huge amount of energy.
But fusion produces far more energy.
The reason why nuclear fusion is not in use is because of the high pressure and temperature needed start it.
The activation energy is high and the energy barrier is very great.
Only the core of the sun naturally favors fusion

learn more:

transmutation brainly.com/question/3433940

#learnwithBrainly

5 0

3 years ago

Read 2 more answers

Give reasons why water should not be used in liquid-glass thermometer

Orlov [11]

Answer:

one of the reasons is that it wets the glass thermometer it also doesn't detect slight changes in temperature of the atmosphere it has a high boiling point I don't know the rest

3 0

3 years ago

Read 2 more answers