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AnnZ [28]
3 years ago
14

How are Earth, the Moon and Sun alligned during a neap tide?

Physics
1 answer:
Tpy6a [65]3 years ago
6 0
Neap tides occur at or immediately after the First Quarter
and Third Quarter moon phases.  At those times, the moon
is 'to the side' of the Earth.  I mean, the sun, Earth, and Moon
make a right angle, with Earth at the vertex.
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2 someone was described in a novel as riding off into the sunset," then they'd be travelling west. o True o False ​
Vanyuwa [196]

Answer: west

Explanation: the sunset always sets in the west.

5 0
2 years ago
You observe a distant galaxy. You find that a spectral line of hydrogen that is shifted from its normal location in the visible
dimulka [17.4K]

Answer:

The galaxy is moving away from us

Explanation:

Galaxy refers to a system of millions or billions of stars accompanied by gas and dust such that they are held together as a result of gravitational attraction.

When we observe a distant galaxy, we find that a spectral line of hydrogen that is shifted from its normal location in the visible part of the spectrum into the infrared part of the spectrum.

It means that the galaxy is moving away from us.

6 0
3 years ago
We calculated the speed of visible light through four substances. What is different about the substances? Lesson: 4.10 Substance
marusya05 [52]

Answer:

it's to dense

Explanation:

3 0
3 years ago
A fence 8 ft high​ (w) runs parallel to a tall building and is 24 ft​ (d) from it. Find the length​ (L) of the shortest ladder t
AveGali [126]

Answer:

25.3 ft

Explanation:

The illustration of the problem is shown the attached image.

The length of the ladder can be calculated using the Pythagoras theorem:

Hypotenuse^2 = opposite^2 + adjacent^2

The hypotenuse is the length of the ladder.

Hypotenuse = \sqrt{opposite^2 + adjacent^2}

L^2 = BC^2 + (24 + AE)^2........1

Triangle ABC is similar to triangle AEF, hence:

\frac{BC}{8} = \frac{AE + 24}{AE}

BC = \frac{8(AE + 24)}{AE}.................2

Substitute 2 into 1

L^2 = (\frac{8(AE + 24)}{AE})^2 + (24 + AE)^2

Let AE = x

L^2 = (\frac{8x + 192}{x})^2 + (24 + x)^2

    = (8 + \frac{192}{x})^2 + (24 + x)^2

Minimize L with respect to x.

2\frac{dL}{dx} = 2(8 + \frac{192}{x})(-\frac{192}{x^2}) + 2(24 + x)

       =

5 0
3 years ago
A student needs to prepare 100.0 mL of vitamin C solution according to the directions in Part 1 of the experiment. S/he weighs o
Rudiy27

Answer:

4.99 mg of vitamin C are in the beaker.

Explanation:

Given that,

Weight of vitamin = 0.0499 g

Molar mass = 176.124 g/mol

Weight of water = 100.0 ml

We need to calculate the mg of vitamin C in the beaker

We dissolve 0.0499 g vitamin C in water to from 100.0 ml solution.

100 ml solution contain 49.9 mg vitamin C

Now, we take 10 ml of this vitamin C solution in breaker

Since, 100 ml solution =49.9 mg vitamin C

Therefore,

10\ ml\ solution =\dfrac{10\times49.9}{100}

10\ ml\ solution =4.99\ mg

Hence, 4.99 mg of vitamin C are in the beaker.

4 0
3 years ago
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