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makkiz [27]
3 years ago
11

Y varies jointly as x and z z. If y = 6 when x = 3 and z = 9, find y when x = 4 and z = 3.6.

Mathematics
1 answer:
masha68 [24]3 years ago
3 0

Answer:

  y = (8/5)√10

Step-by-step explanation:

You seem to have ...

  y=kx\sqrt{z}

We can find k from the given values ...

  \dfrac{y}{x\sqrt{z}}=k=\dfrac{6}{3\sqrt{9}}=\dfrac{6}{3\cdot 3}=\dfrac{2}{3}

Then for the new values, ...

  y=\dfrac{2}{3}\cdot 4\sqrt{3.6}=\dfrac{8\sqrt{90}}{3\cdot 5}=\dfrac{8\sqrt{10}}{5}

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