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Tpy6a [65]
3 years ago
14

Simplify the complex fraction. x+4x/y/7/3x

Mathematics
2 answers:
kotykmax [81]3 years ago
7 0

Answer:

\frac{15x^2}{7y}

Step-by-step explanation:

The given complex fraction is:

\frac{\frac{x+4x}{y}}{\frac{7}{3x}}

Upon solving, we get

=\frac{x+4x}{y}{\times}\frac{3x}{7}

=\frac{3x(x+4x)}{7y}

=\frac{3x(5x)}{7y}

=\frac{15x^2}{7y}

Thus, \frac{\frac{x+4x}{y}}{\frac{7}{3x}}=\frac{15x^2}{7y}

which is the required simplified form.

lora16 [44]3 years ago
3 0
I hope this helps la la la

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<u>Answer:</u>

x = 4 (extraneous solution)

<u>Step-by-step explanation:</u>

\frac { 4 } { x - 4 } = \frac { x } { x - 4 } - \frac { 4 } { 3 } \\ \frac { 4 } { x - 4 } - \frac { x } { x - 4 } = - \frac { 4 } { 3 } \\ \frac { 4 - x } { x - 4 } = - \frac { 4 } { 3 } \\ 3 ( 4 - x ) = - 4 ( x - 4 ) \\ 1 2 - 3 x = - 4 x + 1 6 \\ 4 x - 3 x = 1 6 - 1 2 \\ x = 4 \\

This solution is extraneous. Reason being that even if it can be solved algebraically, it is still not a valid solution because if we substitute back x=4, we will get two fractions with zero denominator which would be undefined.

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(ANSWER ASAP) Solve the inequality. ​
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3 years ago
a storeroom 21 feet long, 15 feet wide, and 11 feet high was enlarged to a length of 25 feet and a width of 17 feet. how many cu
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Step-by-step explanation:

       Initial dimensions of the storeroom were 21\text{ }ft length, 15\text{ }ft width and 11\text{ }ft height.

       The room is in the shape of a cuboid. Volume of a cuboid = V=l\times b\times h, where l,b,h are the length, width and height of the cuboid.

       So, Volume of storeroom initially = 21\text{ }ft\text{ }\times15\text{ }ft\text{ }\times11\text{ }ft\text{ }=3465\text{ }ft^{3}\text{ }

       Finally, the length was increased to 25\text{ }ft and width to 17\text{ }ft.

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       Increase in volume = 4675\text{ ft}^{3}-3465\text{ ft}^{3}=1210\text{ ft}^{3}

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