Question

Simplify the complex fraction. x+4x/y/7/3x

Answer 1

Answer:

$\frac{15x^2}{7y}$

Step-by-step explanation:

The given complex fraction is:

$\frac{\frac{x+4x}{y}}{\frac{7}{3x}}$

Upon solving, we get

=$\frac{x+4x}{y}{\times}\frac{3x}{7}$

=$\frac{3x(x+4x)}{7y}$

=$\frac{3x(5x)}{7y}$

=$\frac{15x^2}{7y}$

Thus, $\frac{\frac{x+4x}{y}}{\frac{7}{3x}}=\frac{15x^2}{7y}$

which is the required simplified form.

Answer 2

I hope this helps la la la