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Aleks04 [339]
2 years ago
7

Keenan currently does a total of 888 pushups each day. He plans to increase the number of pushups he does each day by 222 pushup

s until he is doing a total of 303030 pushups each day.
Which equation can we use to determine xxx, the number of days that it will take Keenan to reach his goal?
Choose 1 answer:
Choose 1 answer:

(Choice A)
A
8+2x=308+2x=308, plus, 2, x, equals, 30

(Choice B)
B
(8+2)x=30(8+2)x=30left parenthesis, 8, plus, 2, right parenthesis, x, equals, 30

(Choice C)
C
8(2+x)=308(2+x)=308, left parenthesis, 2, plus, x, right parenthesis, equals, 30

(Choice D)
D
8+2+x=308+2+x=30
Mathematics
1 answer:
marishachu [46]2 years ago
4 0

Answer:

8 + 2x = 30

Step-by-step explanation:

Given,

The initial number of push-ups he does in each day = 8,

And, the number of push-ups, he increases per day = 2,

Let x be the number of days after he will reach his target of 30 push-ups,

Since, the number of push-ups she will increase in x days = 2x,

Thus, the number of push-ups she will do after x days = 8 + 2x,

⇒ 8 + 2x = 30, which is the required equation.

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A school paid $31.25 for each calculator. If the school bought x calculators, how much did they pay?
Katyanochek1 [597]

Answer:

31.25×

Step-by-step explanation:

suppose that the value of x was 3 . that would mean that they bought 3 calculators .

if one calculator is $31.25 then 3 would be $31.25× 3

the same rule would apply for x

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3 years ago
What is the value of (8 – 5)!?
Lubov Fominskaja [6]
<span>(8-5)!=3!=6</span>
7 0
3 years ago
The height h of a projectile is a function of the time t it is in the air. the height in feet for t seconds is given by the func
alexgriva [62]

Domain means the values of independent variable(input) which will give defined output to the function.

Given:

The height h of a projectile is a function of the time t it is in the air. The height in feet for t seconds is given by the function

h(t)=-16t^2 + 96t

Solution:

To get defined output, the height h(t) need to be greater than or equal to zero. We need to set up an inequality and solve it to find the domain values.

To \; find \; domain:\\\\h(t) \geq0\\\\-16t^2+96t \geq  0\\Factoring \; -16t \; in \; the \; left \; side \; of \; the \; inequality\\\\-16t(t-6) \geq  0\\Step \; 1: Find \; Boundary \; Points \; by \; setting \; up \; above \; inequality \; to \; zero.\\\\t(t-6)=0\\Use \; zero \; factor \; property \; to \; solve\\\\t=0 \; (or) \; t = 6\\\\Step \; 2: \; List \; the \; possible  \; solution \; interval \; using \; boundary \; points\\(- \infty,0], \; [0, 6], \& [6, \infty)

Step \; 3:Pick \; test \; point \; from \; each \; interval \; to \; check \; whether \\\; makes \; the \; inequality \; TRUE \; or \; FALSE\\\\When \; t = -1\\-16(-1)(-1-6) \geq  0\\-112 \geq  0 \; FALSE\\(-\infty, 0] \; is \; not \; solution\\Also \; Logically \; time \; t \; cannot \; be \; negative\\\\When \; t = 1\\-16(1)(1-6) \geq  0\\80 \geq  0 \; TRUE\\ \; [0, 6] \; is \; a \; solution\\\\When \; t = 7\\-16(7)(7-6) \geq  0\\-112 \geq  0 \; FALSE\\ \; [6, -\infty) \; is \; not \; solution

Conclusion:

The domain of the function is the time in between 0 to 6 seconds

0 \leq  t \leq  6

The height will be positive in the above interval.

7 0
3 years ago
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High school students across the nation compete in a financial capability challenge each year by taking a National Financial Capa
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Answer:

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Step-by-step explanation:

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If X \sim N (\mu, \sigma^{2}), then z=\frac{X-\mu}{\sigma}, is a standard normal variate with mean, E (<em>Z</em>) = 0 and Var (<em>Z</em>) = 1. That is, Z \sim N (0, 1).

The distribution of these <em>z</em>-scores is known as the standard normal distribution.

The <em>z</em>-score is a standardized form of the raw score, <em>X</em>. It is a numerical measurement of the relationship between a value (<em>X</em>) and the mean (<em>µ</em>) in terms of the standard deviation (<em>σ</em>). A <em>z</em>-score of -1 implies that the data value is 1 standard deviation below the mean. And a <em>z</em>-score of 1 implies that the data value is 1 standard deviation above the mean.

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That is, P (X > x) = 0.23.

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The value of <em>z</em> for this probability value is:

<em>z</em> = 0.74.

*Use a <em>z</em>-table.

Thus, the students have to score 0.74 standard deviations above the mean to be publicly recognized.

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