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PSYCHO15rus [73]
3 years ago
11

Which statement accurately describes the origin and expansion of the universe? As the universe continues to expand, it gradually

gets warmer. Galaxies that are farther away are moving away more slowly. Cosmic background radiation is leftover thermal energy from the big bang. Stars and galaxies formed almost immediately after the big bang occurred.
Chemistry
2 answers:
irinina [24]3 years ago
7 0

Answer:C on EDG2020

Explanation:

dimulka [17.4K]3 years ago
5 0

The answer is; Cosmic background radiation is leftover thermal energy from the big bang.

Called the coming microwave background the  weak radiation fills the universe more or less uniformly. This radiation is the fossil remnants of the postulated big band at the beginning of the universe. The photos produced at the time continue to travel through the universe growing fainter over time and have fallen in the microwave range of the electromagnetic spectrum now.


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You are given a solid that is a mixture of na2so4 and k2so4.
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Here we have to calculate the amount of SO_{4}^{2-} ion present in the sample.

In the sample solution 0.122g of SO_{4}^{2-} ion is present.

The reaction happens on addition of excess BaCl₂ in a sample solution of potassium sulfate (K₂SO₄) and sodium sulfate [(Na)₂SO₄] can be written as-

K₂SO₄ = 2K⁺ +  SO_{4}^{2-}

(Na)₂SO₄=2Na⁺ +  SO_{4}^{2-}

Thus, BaCl₂+  SO_{4}^{2-} = BaSO₄↓ + 2Cl⁻ .

(Na)₂SO₄ and  K₂SO₄ is highly soluble in water and the precipitation or the filtrate is due to the BaSO₄ only. As a precipitation appears due to addition of excess BaCl₂ thus the total amount of  SO_{4}^{2-} ion is precipitated in this reaction.  

The precipitate i.e. barium sulfate (BaSO₄)is formed in the reaction which have the mass 0.298g.

Now the molecular weight of BaSO₄ is 233.3 g/mol.

We know the molecular weight of sulfate ion (SO_{4}^{2-}) is 96.06 g/mol. Thus in 1 mole of BaSO₄ 96.06 g of SO_{4}^{2-} ion is present.

Or. we may write in 233.3 g of BaSO₄ 96.06 g of SO_{4}^{2-} ion is present. So in 1 g of BaSO₄ \frac{96.06}{233.3}=0.411 g of SO_{4}^{2-} ion is present.

Or, in 0.298 g of the filtered mass (0.298×0.411)=0.122g of SO_{4}^{2-} ion is present.        

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