Q3.) acidic
q4.)that the solution is acidic
q5.)that the solution is alkaline
Answer:
1.05 L
Explanation:
There is some info missing I think this is the original question.
<em>A laboratory experiment requires 250 millimeters of water boiling. it also requires 100 mills of water for a cooling process. If a student performs the experiment three times, how much total water will the student need? Give your answer in liters.</em>
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Step 1: Calculate the volume required for each experiment.
The volume required is the sum of the volumes used: 250 mL + 100 mL = 350 mL
Step 2: Calculate the volume required for the 3 experiments
We have to multiply the volume required for each experiment by 3.
3 × 350 mL = 1050 mL
Step 3: Convert the volume to liters
We use the relation 1 L = 1000 mL.
1050 mL × (1 L/1000 mL) = 1.05 L
Answer:
0.3mol C8H18
Explanation:
For this we must first look at the reaction taking place:
C8H18+O2 --> H2O + CO2
Balancing the equation we get:
2(C8H18)+25(O2) --> 18(H2O) + 16(CO2)
Form there we now need to know how many moles of Octane are needed to produce 2.4moles of H2O. The conversion is as follows:
2.4molH2O ((2mol of C8H18)/(18mol of H2O)) = 0.3mol C8H18
Answer: true
Explanation:
In chemical reactions, an energy barrier exists between reactants and products. The magnitude of this energy barrier determines the rate of reaction. A lesser energy barrier implies that reactants are converted to products faster since the energy required is not too much. On the other hand, a large energy difference between reactants and products will lead to a slow reaction with very poor yield of products if any.
Like A B C D or like a mailed letter
