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2 years ago

7

Thompson High School had a population of 1800 students in 2010. Every year since then, the population has grown by 50 students a

year. Write a formula to model this situation if you let 2010 be t = 0.
A) P = 210 + 50t
B) P = 1800 + 50t
C) P = 2010 + 50t
D) P = 1800 - 50t

1 answer:

Scorpion4ik [409]2 years ago

3 0

I believe it would be B but I'm not 100% sure. Like i warn everyone, TRUST SOMEONE ELSE BEFORE TRUSTING ME. I would hate to see you get the wrong answer cause of me...

Best Hopes,

Cupkake~

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Answer:

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Step-by-step explanation:

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Use the grouping method to factor this polynomial. <br><br> x^3+2x^2+7x+14

Eva8 [605]

x

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2 years ago

Right triangle ABC is similar to right triangle DEF. If the side lengths for triangle ABC are 15, 20, 25, respectively, which va

solniwko [45]

Answer:

$A = 15$ $B = 20$ $C = 25$

$D = 30$ $E = 40$ $F = 50$

$D = 3$ $E = 4$ $F = 5$

Step-by-step explanation:

Given

Similar Triangles: ABC and DEF

$A = 15$

$B = 20$

$C = 25$

Required

Determine the sides of DEF

No options were given, so I will solve on a general terms.

Since both triangles are similar, then the following relationship exists.

DEF = ABC * n

i.e.

$D = A * n$ $E = B * n$ $F = C * n$

Where

$n = Scale\ Factor$

Assume n = 2.

So, we have:

$D = A * n$

$D =15 *2$

$D = 30$

$E = B * n$

$E = 20 * 2$

$E = 40$

$F = C * n$

$F = 25 * 2$

$F = 50$

Assume $n = \frac{1}{5}.$

So, we have:

$D = A * n$

$D =15 *\frac{1}{5}$

$D = 3$

$E = B * n$

$E = 20 * \frac{1}{5}$

$E = 4$

$F = C * n$

$F = 25 * \frac{1}{5}$

$F = 5$

So, the possible sides are:

$A = 15$ $B = 20$ $C = 25$

$D = 30$ $E = 40$ $F = 50$

$D = 3$ $E = 4$ $F = 5$

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Sladkaya [172]

<u>Given</u>:

Given that the side of the regular polygon is 16 feet.

We need to determine the area of the polygon.

<u>Area of the polygon:</u>

The area of the polygon can be determined using the formula,

$Area =\frac{s^2 n}{4 \ tan \frac{180}{n}}$

where n is the number of sides,

s is the side length.

Substituting n = 3 and s = 16, we get;

$Area =\frac{16^2 (3)}{4 \ tan \frac{180}{3}}$

Simplifying, we get;

$Area =\frac{(256) (3)}{4 \ tan \ 60}$

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Dividing, we get;

$Area = 110.85$

Rounding off to the nearest tenth, we have;

$Area = 110.9$

Thus, the area of the regular polygon is 110.9 square units.

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