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Leona [35]
4 years ago
12

5. If you are about to be hit from behind, your best course of action is to brake gently and stop the car

Physics
1 answer:
geniusboy [140]4 years ago
5 0
The answer is true and when they do hit you pull off to the side and call it in
You might be interested in
How many electrons must be added to an object to give it an overall net charge of -3.0 x 10^-7 C? The charge of an electron is -
katovenus [111]

The number of electrons is 1.9\cdot 10^{12}

Explanation:

The total net charge on a negatively-charged object is given by

Q=Ne

where:

N is the number of excess electrons

e is the charge of a single electron

In this problem, we have

Q=-3.0\cdot 10^{-7}C is the overall charge of the object

e=-1.602\cdot 10^{-19}C is the charge of one electron

Solving the equation for N, we find:

N=\frac{Q}{e}=\frac{-3.0\cdot 10^{-7}}{-1.602\cdot 10^{-19}}=1.9\cdot 10^{12}

Learn more about electrons and other particles:

brainly.com/question/2757829

#LearnwithBrainly

6 0
3 years ago
Paco was driving his scooter west with an initial velocity of 4 m/s. He accelerates at 0.5 m/s2 for 30 seconds. What is his fina
Kipish [7]

Answer:

19m/s

Explanation:

U= 4m/s

a = 0.5m/s²

t= 30s

V= U+at

= 4+15

=19m/s

7 0
3 years ago
A river flows with a uniform velocity vr. A person in a motorboat travels 1.22 km upstream, at which time she passes a log float
storchak [24]

Answer:

 t ’= \frac{1450}{0.6499 + 2 v_r},  v_r = 1 m/s       t ’= 547.19 s

Explanation:

This is a relative velocity exercise in a dimesion, since the river and the boat are going in the same direction.

By the time the boat goes up the river

        v_b - v_r = d / t

By the time the boat goes down the river

        v_b + v_r = d '/ t'

let's subtract the equations

       2 v_r = d ’/ t’ - d / t

       d ’/ t’ = 2v_r + d / t

       t' = \frac{d'}{ \frac{d}{t}+ 2 v_r }

In the exercise they tell us

         d = 1.22 +1.45 = 2.67 km= 2.67 10³ m

         d ’= 1.45 km= 1.45 1.³ m

at time t = 69.1 min (60 s / 1min) = 4146 s

the speed of river is v_r

      t ’= \frac{1.45 \ 10^3}{ \frac{ 2670}{4146} \  + 2 \ v_r}

      t ’= \frac{1450}{0.6499 + 2 v_r}

In order to complete the calculation, we must assume a river speed

          v_r = 1 m / s

       

let's calculate

      t ’= \frac{ 1450}{ 0.6499 + 2 \ 1}

      t ’= 547.19 s

8 0
3 years ago
What happens to the shift in wavelength of the x rays if we increase the mass of the target?
andrew-mc [135]

To solve this problem it is necessary to express the term of the wavelength of continuous x-rays according to the Planck constant, the speed of light, the charge of the electron and the voltage. This definition is expressed mathematically as

\lambda = \frac{hc}{eV}

Here,

h is Planck's constant

c is speed of light

e is charge of electron

V is the potential to which the electrons are accelerated.

From this definition we can see that the wavelength is independent of the mass of the target material. Therefore the wavelength will remain the same.

5 0
3 years ago
What are the balanced forces for someone in a parachute?
olasank [31]
A. Gravity pulls you when air resistance to parachute makes it slow
4 0
2 years ago
Read 2 more answers
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