Answer:
y = 43.55 + 2.15t
Explanation:
We were told that in 1983, the per capita consumption was 37.1 pounds, and in 1989 it was 50 pounds.
If we assume t = 0 corresponds to year 1980. Then, for 1983 it will be t = 3 and for 1989,it will be t = 9.
Thus, expressing the information as ordered pairs, we have; (3,37. 1) and (9,50).
Let us now find slope of the linear function:
m1 = (y2 - y1)/(t2 - t1)
m1 = (50 - 37.1)/(9 - 3)
m1 = 2.15
So, we can find the linear equation as;
y - 37.1 = 2.15(t - 3)
y = 37.1 + 2.15t - 6.45
y = 43.55 + 2.15t
Answer:
Explanation:
At constant pressure , work done by gas = P x ΔV where P is pressure and ΔV is change in volume
ΔV = 9.2 - 5.6 = 3.6 L
3.6 L = 3.6 x 10⁻³ m³
ΔV = 3.6 x 10⁻³ m³
P = 3.7 x 10³ Pa
So work done
= 3.7 x 10³ x 3.6 x 10⁻³ J
= 13.32 J .
( c ) is the answer , because work is done by the gas so it will be positive.
As its charge, proton -a positive charged molecule at the center of an atom- is the opposite of the electron -the particle which is orbiting the center of an atom.
Given values:
Mass of the steel ball, m = 100 g = 0.1 kg
Height of the steel ball, h1 = 1.8 m
Rebound height, h2 = 1.25 m
a. PE= mgh
0.1 x 9.8 x 1.8 =
1.764 Joules
b. KE = PE ->
1.764 Joules
c. KE= 1/2 mv square
so v = square root 2ke/m
square root 2 x 1.764/ 0.1
= 5.93 m/s
d. KE=PE=mgh square
0.1 x 9.8 x 1.21 =
1.186 joules
velocity of rebond is square root 2x 1.186/ 0.1 = 4.87 m/s
Answer:
Explanation:
To solve this problem, we can use the following suvat equation:
where
is the vertical displacement of the frog
is the initial vertical velocity
t is the time
a is the acceleration
We have chosen this formula because apart from , all the other quantities are known. In fact:
is the vertical displacement
t = 2 s is the total time of flight
is the acceleration due to gravity (negative because it is downward)
Therefore, solving for , we find the initial velocity of the frog:
