All categories

2 years ago

How many kilograms of chlorine are in 21 kg of CF2Cl2

Chemistry

2 answers:

Aloiza [94]2 years ago

6 0

Answer : The mass of chlorine present in sample is 12.32 kilograms.

Explanation : Given,

Mass of $CF_2Cl_2$ = 21 kg = 21000 g (1 kg = 1000 g)

First we have to calculate the moles of $CF_2Cl_2$ .

Molar mass of $CF_2Cl_2$ = 121 g/mole

$\text{ Moles of }CF_2Cl_2=\frac{\text{ Mass of }CF_2Cl_2}{\text{ Molar mass of }CF_2Cl_2}=\frac{21000g}{121g/mole}=173.5moles$

Now we have to calculate the moles of chlorine.

In the molecule $CF_2Cl_2$ , there are 1 mole of carbon, 2 moles of fluorine and 2 moles of chlorine.

As, 1 mole of $CF_2Cl_2$ contains 2 moles of chlorine

So, 173.5 moles of $CF_2Cl_2$ contains $173.5\times 2=347$ moles of chlorine

Now we have to calculate the mass of chlorine.

$\text{ Mass of chlorine}=\text{ Moles of chlorine}\times \text{ Molar mass of chlorine}$

Molar mass of chlorine = 35.5 g/mole

$\text{ Mass of chlorine}=(347moles)\times (35.5g/mole)=12318.5g=12.32kg$

Therefore, the mass of chlorine present in sample is 12.32 kilograms.

Alik [6]2 years ago

5 0

21 kg x [(3 x 35.45)/(12.01 + 19.00 + (3 x 35.45))] =

21 kg x (106.35/137.36) = 16.3 kg of chlorine

You just multiply the weight of the material by the fraction of chlorine (by weight). The others are done the same way

You might be interested in

Kitty [74]

Answer:

0.14607220033346532

Explanation:

3 0

2 years ago

Bromine reacts with nitric oxide to form nitrosyl bromide as shown in this reaction: br2(g) + 2 no(g) → 2 nobr(g) a possible mec

Svetach [21]

The overall reaction is given by:

$Br_{2}(g) + 2 NO(g) \rightarrow 2 NOBr(g)$

The fast step reaction is given as:

$NO(g) + Br_{2}(g) \rightleftharpoons NOBr_{2}(g) (fast; k_{eq}= \frac{k_{1}}{k_{-1}})$

The slow step reaction is given as:

$NOBr_{2}(g) + NO(g) \rightarrow 2 NOBr(g)$ (slow step $k_{2}$ )

Now, the expression for the rate of reaction of fast reaction is:

$r_{1}=k_{1}[NO][Br_{2}]-k_{-1}[NOBr_{2}]$

The expression for the rate of reaction of slow reaction is:

$r_{2}=k_{2}[NOBr_{2}] [NO]$

Slow step is the rate determining step. Thus, the overall rate of formation is the rate of formation of slow reaction as $[NOBr_{2}]$ takes place in this reaction.

The expression of rate of formation is:

$\frac{d(NOBr)}{dt}=r_{2}$

= $k_{2}[NOBr_{2}][NO]$ (1)

Now, consider that the fast step is always is in equilibrium. Therefore, $r_{1}=0$

$k_{1}[NO][Br_{2}]= k_{-1}[NOBr_{2}]$

$[NOBr_{2}] = \frac{k_{1}}{k_{-1}}[NO][Br_{2}]$

Substitute the value of $[NOBr_{2}]$ in equation (1), we get:

$\frac{d(NOBr)}{dt}=k_{2}[NOBr_{2}][NO]$

= $k_{2} \frac{k_{1}}{k_{-1}}[NO][Br_{2}][NO]$

= $\frac{k_{1}k_{2}}{k_{-1}}[NO]^{2}[Br_{2}]$

Thus, rate law of formation of $NOBr$ in terms of reactants is given by $\frac{k_{1}k_{2}}{k_{-1}}[NO]^{2}[Br_{2}]$ .

4 0

2 years ago

Is this right:) please tell me

viva [34]

Answer:

I think that:

The tendency of an object to resist changes in motion: inertia

Attractive force:gravity

And everything else is right

Explanation:

I am not a physicist

But I passed physics with an A

4 0

2 years ago

Please help i'm being timed

Bad White [126]

a. KCl = strong electrolyte

b. CCl4 = non-electrolyte

c. LiCl = strong electrolyte

d. Na2SO4 = strong electrolyte

5 0

2 years ago

Ammonia chemically reacts with oxygen gas to produce nitric oxide and water . What mass of ammonia is consumed by the reaction o

prohojiy [21]

The chemical equation represents the reaction describes is;
4NH3 + 5O2 = 4NO + 6H2O

Therefore 4 moles of NH3 reacts with 5 moles of O2.
1 mole of O2 (molar mass) = 2 * 16 = 32g.
5 moles of O2 = 5 * 32 = 160g
4 moles of NH3 = 4 (14 + 3*1) = 68g

Therefore, 68g of NH3 reacts with 160g of O2.
But, we have only 4.5 g of oxygen.
68g reacts with 160g
Xg reacts with 4.5
X = 68*4.5 / 160 = 1.9125g

6 0

2 years ago