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Stels [109]
3 years ago
15

How many kilograms of chlorine are in 21 kg of CF2Cl2

Chemistry
2 answers:
Aloiza [94]3 years ago
6 0

Answer : The mass of chlorine present in sample is 12.32 kilograms.

Explanation :  Given,

Mass of CF_2Cl_2 = 21 kg = 21000 g     (1 kg = 1000 g)

First we have to calculate the moles of CF_2Cl_2.

Molar mass of CF_2Cl_2 = 121 g/mole

\text{ Moles of }CF_2Cl_2=\frac{\text{ Mass of }CF_2Cl_2}{\text{ Molar mass of }CF_2Cl_2}=\frac{21000g}{121g/mole}=173.5moles

Now we have to calculate the moles of chlorine.

In the molecule CF_2Cl_2, there are 1 mole of carbon, 2 moles of fluorine and 2 moles of chlorine.

As, 1 mole of CF_2Cl_2 contains 2 moles of chlorine

So, 173.5 moles of CF_2Cl_2 contains 173.5\times 2=347 moles of chlorine

Now we have to calculate the mass of chlorine.

\text{ Mass of chlorine}=\text{ Moles of chlorine}\times \text{ Molar mass of chlorine}

Molar mass of chlorine = 35.5 g/mole

\text{ Mass of chlorine}=(347moles)\times (35.5g/mole)=12318.5g=12.32kg

Therefore, the mass of chlorine present in sample is 12.32 kilograms.

Alik [6]3 years ago
5 0

21 kg x [(3 x 35.45)/(12.01 + 19.00 + (3 x 35.45))] =  

21 kg x (106.35/137.36) = 16.3 kg of chlorine  

You just multiply the weight of the material by the fraction of chlorine (by weight). The others are done the same way

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Complete question is;

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