A car with a total mass of 1800 kg (including passengers) is driving down a washboard road with bumps spaced 4.9 m apart. The ri
2 answers:
Answer:
k=96.16 kN/m
Explanation:
Maximum amplitude is achieved, when the system operated in the resonance- frequency of the bumps is equal to the natural frequency of the spring-mass system.
Frequency of the bumps, as an input force:
f=V/d, where d- distance between the bumps and V- velocity of the resonance.
From the natural frequency of the spring- mass system, we can get:
For the given problem, then the value of k, can be found as:
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Answer:
Explanation:
From the second law of Newton movement laws, we have:
, and we know that a is the acceleration, which definition is:
, so:
The next step is separate variables and integrate (the limits are at this way because at t=0 the block was at rest (v=0):
(This is the indefinite integral), the definite one is:
Answer:
V=15.3 m/s
Explanation:
To solve this problem, we have to use the energy conservation theorem:
the elastic potencial energy is given by:
The work is defined as:
this work is negative because is opposite to the movement.
The gravitational potencial energy at 2.5 m aboves is given by:
the gravitational potential energy at the ground and the kinetic energy at the begining are 0.