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Rzqust [24]
3 years ago
7

A block is 10cm long, 5cm wide and 2cm high and weighs 100g. What is the volume of the block? What is the density?

Physics
1 answer:
Ivahew [28]3 years ago
5 0

Answer:

1gm/cm^3

Explanation:

its the answer

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The number of<br> • in the atom of an element determines its chemical properties.
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Yes, the number of electrons determines the chemical properties of the atom.

Explanation:

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Theorem: there is no smallest positive rational number.theorem: there is no smallest positive rational number. a proof by contra
matrenka [14]

Assume there is a smallest rational integer that has the following form: a/b

Then observe that we can define a/(b+1), which is strictly less than a/b because its divisor is bigger and is rational because it is the product of two numbers. Due to the contradiction created by our original claims that a/b is the smallest rational number that is possible, we might conclude that there is no such thing as the smallest rational number.

There can therefore be no smallest rational number because we may always define a smaller rational number than the one we now possess.

<h3>What is Rational number ?</h3>

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5 0
1 year ago
A guitar string with a linear mass density of 2.0 g/m is stretched between two vertical rods that are 65 cm apart. The string ho
Rudiy27

Answer:

717 Hz

Explanation:

<u>solution:</u>

The wave with three antinodes has m = 3. Thus, f_3 = 3f_1 and so the fundamental frequency of the string is  

f_1 =f_3/3

    =430 Hz/3

    =143 Hz

Thus, the frequency of the fifth harmonic is

f_5 = 5*f_1

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7 0
3 years ago
Describing Waves
LiRa [457]

Answer:Direct them straight across

Explanation:

3 0
3 years ago
Read 2 more answers
An object of mass 3.4 kg is moving in a straight line with kinetic energy 59.177 J. A force is applied in the direction of its m
rusak2 [61]

Answer:

Its momentum is multiplied by a factor of 1.25

Explanation:

First, we <u>calculate the initial velocity of the object</u>:

  • K = 0.5 * m * v₁²
  • 59.177 J = 0.5 * 3.4 kg * v₁²
  • v₁ = 5.9 m/s

With that velocity we can <u>calculate the initial momentum of the object</u>:

  • p₁ = v₁ * m
  • p₁ = 20.06 kg·m/s

Then we <u>calculate the velocity of the object once its kinetic energy has increased</u>:

  • (59.177 J) * 1.57 = 0.5 * 3.4 kg * v₂²
  • v₂ = 7.4 m/s

And <u>calculate the second momentum of the object</u>:

  • p₂ = v₂ * m
  • p₂ = 25.16 kg·m/s

Finally we <u>calculate the factor</u>:

  • p₂/p₁ = 1.25
3 0
2 years ago
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